Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Vd = 0.7 L/kgC = 25 mg/LLD = ?89 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 89 kg needs a loading dose of vancomycin to reach a level of 25 mg/L straight away. The volume of distribution is 0.7 L/kg. Find the loading dose LD in mg.

89 kgVd = 0.7 L/kgC = 25 mg/L
LD = mg
2.Easy
Vd = 0.5 L/kgC = 15 mg/LLD = ?72 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 72 kg needs a loading dose of theophylline to reach a level of 15 mg/L straight away. The volume of distribution is 0.5 L/kg. Find the loading dose LD in mg.

72 kgVd = 0.5 L/kgC = 15 mg/L
LD = mg
3.Medium
Vd = 0.7 L/kgC = 20 mg/LLD = ? mg54 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). A 54 kg patient is to be loaded intravenously with phenytoin sodium to reach a phenytoin level of 20 mg/L. The volume of distribution is 0.7 L/kg and the salt factor is S = 0.92. Find the loading dose LD of phenytoin sodium in mg.

54 kgVd = 0.7 L/kgC = 20 mg/LS = 0.92
LD = mg
4.Medium
Vd = 0.5 L/kgC = 12 mg/LLD = ? mg79 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 79 kg patient is to be loaded intravenously with aminophylline to reach a theophylline level of 12 mg/L. The volume of distribution is 0.5 L/kg and the salt factor is S = 0.8. Find the loading dose LD of aminophylline in mg.

79 kgVd = 0.5 L/kgC = 12 mg/LS = 0.8
LD = mg
5.Hard
0.1110t (h)C (mg/L)Cpeak​ = 7τ = ?Ctrough​ = 0.5

Practice exercise (made-up values, not clinical guidance). A patient's gentamicin half-life is 2 h. The target is a peak of 7 mg/L and a trough of 0.5 mg/L. Assuming rapid IV doses and first-order elimination, what dosing interval τ lets the level fall from the peak to the trough? Round to one decimal place.

t½ = 2 hCpeak = 7 mg/LCtrough = 0.5 mg/L
τ = h
6.Hard
80 kg73 · manSCr 2.2 mg/dLCrCl → τ = ? h

Practice exercise (made-up values, not clinical guidance). A 73-year-old man weighs 80 kg and has a serum creatinine of 2.2 mg/dL (194 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual tobramycin regimen is 120 mg every 8 h for a creatinine clearance of 120 mL/min. Keeping the dose, the interval is lengthened in proportion to the fall in clearance. Find the new dosing interval τ. Round to one decimal place.

73 years80 kgmanSCr = 2.2 mg/dL120 mg q8hCrCl normal 120 mL/min
τ = h

Answer key

  1. 1. LD = 1558 mg
  2. 2. LD = 540 mg
  3. 3. LD = 821.7 mg
  4. 4. LD = 592.5 mg
  5. 5. τ = 7.6 h
  6. 6. τ = 28.4 h

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