Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
0.1110t (h)C (mg/L)6 mg/L5.5 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the gentamicin level is 6 mg/L. The half-life is 2 h, and the drug is eliminated by first-order kinetics. What is the level C 5.5 h later?

C₀ = 6 mg/Lt½ = 2 ht = 5.5 h
C = mg/L
2.Easy
t/t½C/Css (%)100%1f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives lidocaine as a constant IV infusion without a loading dose. The half-life is 1.5 h. What percentage f of the steady-state level has been reached after 1.5 h?

t½ = 1.5 ht = 1.5 h
f = %
3.Medium
Vd = 7 L/kgC = 0.8 mcg/LLD = ? mcg76 kg · S = 1 · F = 0.7

Practice exercise (made-up values, not clinical guidance). A 76 kg patient is to be loaded with digoxin tablets to reach a level of 0.8 mcg/L. The volume of distribution is 7 L/kg and the tablets have a bioavailability F = 0.7. Find the total oral loading dose LD in mcg.

76 kgVd = 7 L/kgC = 0.8 mcg/LF = 0.7
LD = mcg
4.Medium
VCss​ = 2.5 mg/LR = ? mg/minCL = 850 mL/min

Practice exercise (made-up values, not clinical guidance). A patient has a lidocaine clearance of 850 mL/min. What infusion rate R in mg/min keeps the steady-state level at 2.5 mg/L?

CL = 850 mL/minCss = 2.5 mg/L
R = mg/min
5.Hard
0.1110t (h)C (mg/L)Cpeak​ = 8τ = ?Ctrough​ = 1

Practice exercise (made-up values, not clinical guidance). A patient's tobramycin half-life is 4 h. The target is a peak of 8 mg/L and a trough of 1 mg/L. Assuming rapid IV doses and first-order elimination, what dosing interval τ lets the level fall from the peak to the trough? Round to one decimal place.

t½ = 4 hCpeak = 8 mg/LCtrough = 1 mg/L
τ = h
6.Hard
VCss,avg​ = 10 mg/LD = ? mg · q12hCL = 0.05 L/kg/h73 kg · S = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). A 73 kg patient takes oral theophylline (F = 1) every 12 h. The clearance is 0.05 L/kg/h. What dose D in mg gives an average steady-state level of 10 mg/L?

CL = 0.05 L/kg/hτ = 12 hS = 1F = 173 kgCss,avg = 10 mg/L
D = mg

Answer key

  1. 1. C = 0.8919 mg/L
  2. 2. f = 50 %
  3. 3. LD = 608 mcg
  4. 4. R = 2.125 mg/min
  5. 5. τ = 12 h
  6. 6. D = 438 mg

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