Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
110100t (h)C (mg/L)10 mg/L6.5 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the tobramycin level is 10 mg/L. The half-life is 3 h, and the drug is eliminated by first-order kinetics. What is the level C 6.5 h later?

C₀ = 10 mg/Lt½ = 3 ht = 6.5 h
C = mg/L
2.Easy
110100t (h)CC₀t½ = ?C₀/2

Practice exercise (made-up values, not clinical guidance). The elimination rate constant of theophylline in a patient is 0.0866 h⁻¹. Find the half-life t½.

k = 0.0866 h⁻¹
t½ = h
3.Medium
110t (h)C (mg/L)2 h6 mg/L6 h2 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of tobramycin, the level is 6 mg/L at 2 h and 2 mg/L at 6 h. Assume first-order elimination. Find the half-life t½.

C1 = 6 mg/L (2 h)C2 = 2 mg/L (6 h)
t½ = h
4.Medium
Vd = 0.5 L/kgC = 12 mg/LLD = ? mg98 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 98 kg patient is to be loaded intravenously with aminophylline to reach a theophylline level of 12 mg/L. The volume of distribution is 0.5 L/kg and the salt factor is S = 0.8. Find the loading dose LD of aminophylline in mg.

98 kgVd = 0.5 L/kgC = 12 mg/LS = 0.8
LD = mg
5.Hard
77 kg53 · manSCr 2.7 mg/dLCrCl → D = ? mg

Practice exercise (made-up values, not clinical guidance). A 53-year-old man weighs 77 kg and has a serum creatinine of 2.7 mg/dL (239 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual gentamicin dose is 120 mg every 8 h for a creatinine clearance of 100 mL/min. Keeping the interval, the dose is reduced in proportion to the creatinine clearance. Find the adjusted dose D. Round to the nearest whole number.

53 years77 kgmanSCr = 2.7 mg/dL120 mg q8hCrCl normal 100 mL/min
D = mg
6.Hard
0.1110t (h)C (mg/L)Cpeak​ = 7τ = ?Ctrough​ = 0.5

Practice exercise (made-up values, not clinical guidance). A patient's tobramycin half-life is 2.5 h. The target is a peak of 7 mg/L and a trough of 0.5 mg/L. Assuming rapid IV doses and first-order elimination, what dosing interval τ lets the level fall from the peak to the trough? Round to one decimal place.

t½ = 2.5 hCpeak = 7 mg/LCtrough = 0.5 mg/L
τ = h

Answer key

  1. 1. C = 2.227 mg/L
  2. 2. t½ = 8.004 h
  3. 3. t½ = 2.524 h
  4. 4. LD = 735 mg
  5. 5. D = 41 mg
  6. 6. τ = 9.5 h

Full step-by-step solutions: practise this topic on examproblems.com.