Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
110100t (h)CC₀t½ = ?C₀/2

Practice exercise (made-up values, not clinical guidance). The elimination rate constant of vancomycin in a patient is 0.077 h⁻¹. Find the half-life t½.

k = 0.077 h⁻¹
t½ = h
2.Easy
Vd = 0.3 L/kgC = 8 mg/LLD = ?65 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 65 kg needs a loading dose of tobramycin to reach a level of 8 mg/L straight away. The volume of distribution is 0.3 L/kg. Find the loading dose LD in mg.

65 kgVd = 0.3 L/kgC = 8 mg/L
LD = mg
3.Medium
Vd = 0.7 L/kgC = 15 mg/LLD = ? mg62 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). A 62 kg patient is to be loaded intravenously with phenytoin sodium to reach a phenytoin level of 15 mg/L. The volume of distribution is 0.7 L/kg and the salt factor is S = 0.92. Find the loading dose LD of phenytoin sodium in mg.

62 kgVd = 0.7 L/kgC = 15 mg/LS = 0.92
LD = mg
4.Medium
110t (h)C (mg/L)C₀ = 8 mg/Lt½ = 3 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 240 mg of tobramycin. The level back-extrapolated to time zero is 8 mg/L and the half-life is 3 h. Find the clearance CL in L/h.

D = 240 mgC₀ = 8 mg/Lt½ = 3 h
CL = L/h
5.Hard
Vd = 0.3 L/kg0.5 → 10 mg/LD = ? mg96 kg

Practice exercise (made-up values, not clinical guidance). A 96 kg patient on regular gentamicin doses is at steady state. The target is a peak of 10 mg/L and a trough of 0.5 mg/L, and the volume of distribution is 0.3 L/kg. Assuming rapid IV doses, what dose D raises the level from the trough to the peak?

96 kgVd = 0.3 L/kgCpeak = 10 mg/LCtrough = 0.5 mg/L
D = mg
6.Hard
0.1110t (h)C (mg/L)Cpeak​ = 6τ = ?Ctrough​ = 1

Practice exercise (made-up values, not clinical guidance). A patient's gentamicin half-life is 2.5 h. The target is a peak of 6 mg/L and a trough of 1 mg/L. Assuming rapid IV doses and first-order elimination, what dosing interval τ lets the level fall from the peak to the trough? Round to one decimal place.

t½ = 2.5 hCpeak = 6 mg/LCtrough = 1 mg/L
τ = h

Answer key

  1. 1. t½ = 9.002 h
  2. 2. LD = 156 mg
  3. 3. LD = 707.6 mg
  4. 4. CL = 6.931 L/h
  5. 5. D = 273.6 mg
  6. 6. τ = 6.5 h

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