Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
110100t (h)C (mg/L)10 mg/L8.5 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the tobramycin level is 10 mg/L. The half-life is 3 h, and the drug is eliminated by first-order kinetics. What is the level C 8.5 h later?

C₀ = 10 mg/Lt½ = 3 ht = 8.5 h
C = mg/L
2.Easy
110100t (h)CC₀t½ = 2 hC₀/2

Practice exercise (made-up values, not clinical guidance). In a patient, gentamicin has an elimination half-life of 2 h. Find the elimination rate constant k in h⁻¹.

t½ = 2 h
k = h⁻¹
3.Medium
Vd = 0.5 L/kgC = 12 mg/LLD = ? mg93 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 93 kg patient is to be loaded intravenously with aminophylline to reach a theophylline level of 12 mg/L. The volume of distribution is 0.5 L/kg and the salt factor is S = 0.8. Find the loading dose LD of aminophylline in mg.

93 kgVd = 0.5 L/kgC = 12 mg/LS = 0.8
LD = mg
4.Medium
110t (h)C (mg/L)C₀ = 6 mg/Lt½ = 2.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 100 mg of gentamicin. The level back-extrapolated to time zero is 6 mg/L and the half-life is 2.5 h. Find the clearance CL in L/h.

D = 100 mgC₀ = 6 mg/Lt½ = 2.5 h
CL = L/h
5.Hard
Vd = 0.5 L/kg9 → 15 mg/LLD = ? mg59 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 59 kg patient has a theophylline level of 9 mg/L; the target is 15 mg/L. The drug is given intravenously as aminophylline (S = 0.8), and the volume of distribution is 0.5 L/kg. What extra loading dose LD raises the level to the target?

59 kgVd = 0.5 L/kgC = 9 → 15 mg/LS = 0.8
LD = mg
6.Hard
VCss,avg​ = 10 mg/LD = ? mg · q8hCL = 0.03 L/kg/h81 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). An 81 kg patient takes oral aminophylline (S = 0.8, F = 1) every 8 h. The theophylline clearance is 0.03 L/kg/h. What dose D in mg gives an average steady-state level of 10 mg/L?

CL = 0.03 L/kg/hτ = 8 hS = 0.8F = 181 kgCss,avg = 10 mg/L
D = mg

Answer key

  1. 1. C = 1.403 mg/L
  2. 2. k = 0.3466 h⁻¹
  3. 3. LD = 697.5 mg
  4. 4. CL = 4.621 L/h
  5. 5. LD = 221.3 mg
  6. 6. D = 243 mg

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