Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
t/t½C/Css (%)100%4f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives lidocaine as a constant IV infusion without a loading dose. The half-life is 2 h. What percentage f of the steady-state level has been reached after 8 h?

t½ = 2 ht = 8 h
f = %
2.Easy
t/t½C/Css (%)100%4f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives aminophylline as a constant IV infusion without a loading dose. The half-life is 9 h. What percentage f of the steady-state level has been reached after 36 h?

t½ = 9 ht = 36 h
f = %
3.Medium
VCss​ = 12 mg/LR = ? mg/hCL = 0.045 L/kg/h72 kg

Practice exercise (made-up values, not clinical guidance). A 72 kg patient receives a theophylline infusion. The clearance is 0.045 L/kg/h. What infusion rate R in mg/h gives a steady-state level of 12 mg/L?

72 kgCL = 0.045 L/kg/hCss = 12 mg/L
R = mg/h
4.Medium
110t (h)C (mg/L)2 h6 mg/L8 h1.5 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of tobramycin, the level is 6 mg/L at 2 h and 1.5 mg/L at 8 h. Assume first-order elimination. Find the half-life t½.

C1 = 6 mg/L (2 h)C2 = 1.5 mg/L (8 h)
t½ = h
5.Hard
VCss,avg​ = ?750 mg · q12hCL = 3 L/hS = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). A patient receives vancomycin IV every 12 h; the vancomycin clearance is 3 L/h. Each dose is 750 mg of vancomycin. Find the average steady-state level Css,avg.

CL = 3 L/hτ = 12 hS = 1F = 1D = 750 mg
Css,avg = mg/L
6.Hard
53 kg41 · manSCr 2.4 mg/dLfe​ = 0.9D = ? mg

Practice exercise (made-up values, not clinical guidance). A 41-year-old man weighs 53 kg and has a serum creatinine of 2.4 mg/dL (212 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual atenolol dose is 100 mg for a creatinine clearance of 120 mL/min, and a fraction fe = 0.9 of the drug is excreted unchanged by the kidneys. Using the Dettli dose fraction Q = 1 − fe·(1 − CrCl/normal CrCl), find the adjusted dose D. Round to the nearest whole number.

41 years53 kgmanSCr = 2.4 mg/dL100 mgfe = 0.9CrCl normal 120 mL/min
D = mg

Answer key

  1. 1. f = 93.75 %
  2. 2. f = 93.75 %
  3. 3. R = 38.88 mg/h
  4. 4. t½ = 3 h
  5. 5. Css,avg = 20.83 mg/L
  6. 6. D = 33 mg

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