Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Vd = 0.25 L/kgC = 6 mg/LLD = ?107 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 107 kg needs a loading dose of gentamicin to reach a level of 6 mg/L straight away. The volume of distribution is 0.25 L/kg. Find the loading dose LD in mg.

107 kgVd = 0.25 L/kgC = 6 mg/L
LD = mg
2.Easy
t/t½C/Css (%)100%597%

Practice exercise (made-up values, not clinical guidance). A patient starts regular doses of vancomycin, which has a half-life of 12 h. Using the rule that steady state is reached after about five half-lives, after how many hours tss is steady state reached?

t½ = 12 h
tss = h
3.Medium
110100t (h)C (mg/L)C₀ = 10 mg/Lt½ = 2 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 300 mg of gentamicin. The level back-extrapolated to time zero is 10 mg/L and the half-life is 2 h. Find the clearance CL in L/h.

D = 300 mgC₀ = 10 mg/Lt½ = 2 h
CL = L/h
4.Medium
VCss​ = 15 mg/LR = ? mg/hCL = 0.045 L/kg/h83 kg

Practice exercise (made-up values, not clinical guidance). An 83 kg patient receives a theophylline infusion. The clearance is 0.045 L/kg/h. What infusion rate R in mg/h gives a steady-state level of 15 mg/L?

83 kgCL = 0.045 L/kg/hCss = 15 mg/L
R = mg/h
5.Hard
t (h)C (mg/L)Css​15 hC = ?

Practice exercise (made-up values, not clinical guidance). A vancomycin infusion runs at 125 mg/h with no loading dose. The patient's clearance is 5 L/h and the half-life is 10 h. What is the level C after 15 h?

R = 125 mg/hCL = 5 L/ht½ = 10 ht = 15 h
C = mg/L
6.Hard
0.1110t (h)C (mg/L)Cpeak​ = 8τ = ?Ctrough​ = 1

Practice exercise (made-up values, not clinical guidance). A patient's tobramycin half-life is 2 h. The target is a peak of 8 mg/L and a trough of 1 mg/L. Assuming rapid IV doses and first-order elimination, what dosing interval τ lets the level fall from the peak to the trough? Round to one decimal place.

t½ = 2 hCpeak = 8 mg/LCtrough = 1 mg/L
τ = h

Answer key

  1. 1. LD = 160.5 mg
  2. 2. tss = 60 h
  3. 3. CL = 10.4 L/h
  4. 4. R = 56.02 mg/h
  5. 5. C = 16.16 mg/L
  6. 6. τ = 6 h

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