Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
10100t (h)C (mg/L)30 mg/L12 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the vancomycin level is 30 mg/L. The half-life is 12 h, and the drug is eliminated by first-order kinetics. What is the level C 12 h later?

C₀ = 30 mg/Lt½ = 12 ht = 12 h
C = mg/L
2.Easy
Vd = 0.25 L/kgC = 8 mg/LLD = ?70 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 70 kg needs a loading dose of gentamicin to reach a level of 8 mg/L straight away. The volume of distribution is 0.25 L/kg. Find the loading dose LD in mg.

70 kgVd = 0.25 L/kgC = 8 mg/L
LD = mg
3.Medium
110t (h)C (mg/L)C₀ = 6 mg/Lt½ = 3.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 90 mg of gentamicin. The level back-extrapolated to time zero is 6 mg/L and the half-life is 3.5 h. Find the clearance CL in L/h.

D = 90 mgC₀ = 6 mg/Lt½ = 3.5 h
CL = L/h
4.Medium
Vd = 0.7 L/kgC = 15 mg/LLD = ? mg88 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). An 88 kg patient is to be loaded intravenously with phenytoin sodium to reach a phenytoin level of 15 mg/L. The volume of distribution is 0.7 L/kg and the salt factor is S = 0.92. Find the loading dose LD of phenytoin sodium in mg.

88 kgVd = 0.7 L/kgC = 15 mg/LS = 0.92
LD = mg
5.Hard
92 kg63 · manSCr 2.8 mg/dLCrCl → τ = ? h

Practice exercise (made-up values, not clinical guidance). A 63-year-old man weighs 92 kg and has a serum creatinine of 2.8 mg/dL (248 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual vancomycin regimen is 1000 mg every 12 h for a creatinine clearance of 120 mL/min. Keeping the dose, the interval is lengthened in proportion to the fall in clearance. Find the new dosing interval τ. Round to one decimal place.

63 years92 kgmanSCr = 2.8 mg/dL1000 mg q12hCrCl normal 120 mL/min
τ = h
6.Hard
VCss,avg​ = ?200 mg · q8hCL = 0.04 L/kg/h89 kg · S = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). An 89 kg patient takes oral theophylline (F = 1) every 8 h. The clearance is 0.04 L/kg/h. Each dose is 200 mg of theophylline. Find the average steady-state level Css,avg.

CL = 0.04 L/kg/hτ = 8 hS = 1F = 189 kgD = 200 mg
Css,avg = mg/L

Answer key

  1. 1. C = 15 mg/L
  2. 2. LD = 140 mg
  3. 3. CL = 2.971 L/h
  4. 4. LD = 1004 mg
  5. 5. τ = 41 h
  6. 6. Css,avg = 7.022 mg/L

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