Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Vd = 0.5 L/kgC = 10 mg/LLD = ?72 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 72 kg needs a loading dose of theophylline to reach a level of 10 mg/L straight away. The volume of distribution is 0.5 L/kg. Find the loading dose LD in mg.

72 kgVd = 0.5 L/kgC = 10 mg/L
LD = mg
2.Easy
t/t½C/Css (%)100%1.5f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives lidocaine as a constant IV infusion without a loading dose. The half-life is 2 h. What percentage f of the steady-state level has been reached after 3 h?

t½ = 2 ht = 3 h
f = %
3.Medium
VCss​ = 15 mg/LR = ? mg/hCL = 0.04 L/kg/h79 kg

Practice exercise (made-up values, not clinical guidance). A 79 kg patient receives a theophylline infusion. The clearance is 0.04 L/kg/h. What infusion rate R in mg/h gives a steady-state level of 15 mg/L?

79 kgCL = 0.04 L/kg/hCss = 15 mg/L
R = mg/h
4.Medium
110100t (h)C (mg/L)C₀ = 12 mg/Lt½ = 2.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 170 mg of gentamicin. The level back-extrapolated to time zero is 12 mg/L and the half-life is 2.5 h. Find the clearance CL in L/h.

D = 170 mgC₀ = 12 mg/Lt½ = 2.5 h
CL = L/h
5.Hard
Vd = 0.7 L/kg8 → 20 mg/LLD = ? mg52 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). A 52 kg patient has a phenytoin level of 8 mg/L; the target is 20 mg/L. The drug is given intravenously as phenytoin sodium (S = 0.92), and the volume of distribution is 0.7 L/kg. What extra loading dose LD raises the level to the target?

52 kgVd = 0.7 L/kgC = 8 → 20 mg/LS = 0.92
LD = mg
6.Hard
0.1110t (h)C (mg/L)Cpeak​ = 6τ = ?Ctrough​ = 0.5

Practice exercise (made-up values, not clinical guidance). A patient's gentamicin half-life is 2 h. The target is a peak of 6 mg/L and a trough of 0.5 mg/L. Assuming rapid IV doses and first-order elimination, what dosing interval τ lets the level fall from the peak to the trough? Round to one decimal place.

t½ = 2 hCpeak = 6 mg/LCtrough = 0.5 mg/L
τ = h

Answer key

  1. 1. LD = 360 mg
  2. 2. f = 64.64 %
  3. 3. R = 47.4 mg/h
  4. 4. CL = 3.928 L/h
  5. 5. LD = 474.8 mg
  6. 6. τ = 7.2 h

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