Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
110100t (h)C (mg/L)30 mg/L13 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the vancomycin level is 30 mg/L. The half-life is 6 h, and the drug is eliminated by first-order kinetics. What is the level C 13 h later?

C₀ = 30 mg/Lt½ = 6 ht = 13 h
C = mg/L
2.Easy
110100t (h)CC₀t½ = 6 hC₀/2

Practice exercise (made-up values, not clinical guidance). In a patient, theophylline has an elimination half-life of 6 h. Find the elimination rate constant k in h⁻¹.

t½ = 6 h
k = h⁻¹
3.Medium
Vd = 0.7 L/kgC = 15 mg/LLD = ? mg74 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). A 74 kg patient is to be loaded intravenously with phenytoin sodium to reach a phenytoin level of 15 mg/L. The volume of distribution is 0.7 L/kg and the salt factor is S = 0.92. Find the loading dose LD of phenytoin sodium in mg.

74 kgVd = 0.7 L/kgC = 15 mg/LS = 0.92
LD = mg
4.Medium
110100t (h)C (mg/L)C₀ = 9 mg/Lt½ = 2.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 170 mg of tobramycin. The level back-extrapolated to time zero is 9 mg/L and the half-life is 2.5 h. Find the clearance CL in L/h.

D = 170 mgC₀ = 9 mg/Lt½ = 2.5 h
CL = L/h
5.Hard
Vd = 0.7 L/kg4.5 → 15 mg/LLD = ? mg52 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). A 52 kg patient has a phenytoin level of 4.5 mg/L; the target is 15 mg/L. The drug is given intravenously as phenytoin sodium (S = 0.92), and the volume of distribution is 0.7 L/kg. What extra loading dose LD raises the level to the target?

52 kgVd = 0.7 L/kgC = 4.5 → 15 mg/LS = 0.92
LD = mg
6.Hard
t (h)C (mg/L)Css​t = ?90%

Practice exercise (made-up values, not clinical guidance). A vancomycin infusion is started without a loading dose. The half-life in this patient is 10 h. How long t does it take to reach 90% of the steady-state level?

t½ = 10 h90% Css
t = h

Answer key

  1. 1. C = 6.682 mg/L
  2. 2. k = 0.1155 h⁻¹
  3. 3. LD = 844.6 mg
  4. 4. CL = 5.237 L/h
  5. 5. LD = 415.4 mg
  6. 6. t = 33.22 h

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