Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
t/t½C/Css (%)100%597%

Practice exercise (made-up values, not clinical guidance). A patient starts regular doses of digoxin, which has a half-life of 36 h. Using the rule that steady state is reached after about five half-lives, after how many hours tss is steady state reached?

t½ = 36 h
tss = h
2.Easy
t/t½C/Css (%)100%1.5f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives vancomycin as a constant IV infusion without a loading dose. The half-life is 10 h. What percentage f of the steady-state level has been reached after 15 h?

t½ = 10 ht = 15 h
f = %
3.Medium
110100t (h)C (mg/L)1 h10 mg/L6 h3.1 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of gentamicin, the level is 10 mg/L at 1 h and 3.1 mg/L at 6 h. Assume first-order elimination. Find the half-life t½.

C1 = 10 mg/L (1 h)C2 = 3.1 mg/L (6 h)
t½ = h
4.Medium
VCss​ = 12 mg/LR = ? mg/h · S = 0.8CL = 0.035 L/kg/h67 kg

Practice exercise (made-up values, not clinical guidance). A 67 kg patient is to receive an aminophylline infusion (salt factor S = 0.8: 80% of aminophylline is theophylline). The theophylline clearance is 0.035 L/kg/h. What aminophylline infusion rate R in mg/h gives a steady-state theophylline level of 12 mg/L?

67 kgCL = 0.035 L/kg/hCss = 12 mg/LS = 0.8
R = mg/h
5.Hard
t (h)C (mg/L)Css​5 hC = ?

Practice exercise (made-up values, not clinical guidance). A theophylline infusion runs at 20 mg/h with no loading dose. The patient's clearance is 2 L/h and the half-life is 9 h. What is the level C after 5 h?

R = 20 mg/hCL = 2 L/ht½ = 9 ht = 5 h
C = mg/L
6.Hard
0.1110t (h)C (mg/L)Cpeak​ = 6τ = ?Ctrough​ = 1

Practice exercise (made-up values, not clinical guidance). A patient's gentamicin half-life is 2 h. The target is a peak of 6 mg/L and a trough of 1 mg/L. Assuming rapid IV doses and first-order elimination, what dosing interval τ lets the level fall from the peak to the trough? Round to one decimal place.

t½ = 2 hCpeak = 6 mg/LCtrough = 1 mg/L
τ = h

Answer key

  1. 1. tss = 180 h
  2. 2. f = 64.64 %
  3. 3. t½ = 2.959 h
  4. 4. R = 35.17 mg/h
  5. 5. C = 3.196 mg/L
  6. 6. τ = 5.2 h

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