Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
0.1110t (h)C (mg/L)6 mg/L5 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the tobramycin level is 6 mg/L. The half-life is 2 h, and the drug is eliminated by first-order kinetics. What is the level C 5 h later?

C₀ = 6 mg/Lt½ = 2 ht = 5 h
C = mg/L
2.Easy
10100t (h)C (mg/L)25 mg/L10 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the vancomycin level is 25 mg/L. The half-life is 10 h, and the drug is eliminated by first-order kinetics. What is the level C 10 h later?

C₀ = 25 mg/Lt½ = 10 ht = 10 h
C = mg/L
3.Medium
VCss​ = 12 mg/LR = ? mg/h · S = 0.8CL = 0.03 L/kg/h50 kg

Practice exercise (made-up values, not clinical guidance). A 50 kg patient is to receive an aminophylline infusion (salt factor S = 0.8: 80% of aminophylline is theophylline). The theophylline clearance is 0.03 L/kg/h. What aminophylline infusion rate R in mg/h gives a steady-state theophylline level of 12 mg/L?

50 kgCL = 0.03 L/kg/hCss = 12 mg/LS = 0.8
R = mg/h
4.Medium
Vd = 0.5 L/kgC = 12 mg/LLD = ? mg92 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 92 kg patient is to be loaded intravenously with aminophylline to reach a theophylline level of 12 mg/L. The volume of distribution is 0.5 L/kg and the salt factor is S = 0.8. Find the loading dose LD of aminophylline in mg.

92 kgVd = 0.5 L/kgC = 12 mg/LS = 0.8
LD = mg
5.Hard
86 kg80 · manSCr 1.8 mg/dLfe​ = 0.6D = ? mg

Practice exercise (made-up values, not clinical guidance). An 80-year-old man weighs 86 kg and has a serum creatinine of 1.8 mg/dL (159 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual ciprofloxacin dose is 500 mg for a creatinine clearance of 100 mL/min, and a fraction fe = 0.6 of the drug is excreted unchanged by the kidneys. Using the Dettli dose fraction Q = 1 − fe·(1 − CrCl/normal CrCl), find the adjusted dose D. Round to the nearest whole number.

80 years86 kgmanSCr = 1.8 mg/dL500 mgfe = 0.6CrCl normal 100 mL/min
D = mg
6.Hard
t (h)C (mg/L)Css​19 hC = ?

Practice exercise (made-up values, not clinical guidance). A vancomycin infusion runs at 125 mg/h with no loading dose. The patient's clearance is 5 L/h and the half-life is 10 h. What is the level C after 19 h?

R = 125 mg/hCL = 5 L/ht½ = 10 ht = 19 h
C = mg/L

Answer key

  1. 1. C = 1.061 mg/L
  2. 2. C = 12.5 mg/L
  3. 3. R = 22.5 mg/h
  4. 4. LD = 690 mg
  5. 5. D = 319 mg
  6. 6. C = 18.3 mg/L

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