Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
110100t (h)C (mg/L)10 mg/L3.5 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the tobramycin level is 10 mg/L. The half-life is 2.5 h, and the drug is eliminated by first-order kinetics. What is the level C 3.5 h later?

C₀ = 10 mg/Lt½ = 2.5 ht = 3.5 h
C = mg/L
2.Easy
Vd = 0.7 L/kgC = 25 mg/LLD = ?57 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 57 kg needs a loading dose of vancomycin to reach a level of 25 mg/L straight away. The volume of distribution is 0.7 L/kg. Find the loading dose LD in mg.

57 kgVd = 0.7 L/kgC = 25 mg/L
LD = mg
3.Medium
0.1110t (h)C (mg/L)1 h8 mg/L7 h1 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of gentamicin, the level is 8 mg/L at 1 h and 1 mg/L at 7 h. Assume first-order elimination. Find the half-life t½.

C1 = 8 mg/L (1 h)C2 = 1 mg/L (7 h)
t½ = h
4.Medium
110100t (h)C (mg/L)1 h25 mg/L11 h9.3 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of vancomycin, the level is 25 mg/L at 1 h and 9.3 mg/L at 11 h. Assume first-order elimination. Find the half-life t½.

C1 = 25 mg/L (1 h)C2 = 9.3 mg/L (11 h)
t½ = h
5.Hard
t (h)C (mg/L)Css​t = ?90%

Practice exercise (made-up values, not clinical guidance). A vancomycin infusion is started without a loading dose. The half-life in this patient is 6 h. How long t does it take to reach 90% of the steady-state level?

t½ = 6 h90% Css
t = h
6.Hard
0.1110t (h)C (mg/L)Cpeak​ = 6τ = ?Ctrough​ = 0.5

Practice exercise (made-up values, not clinical guidance). A patient's gentamicin half-life is 4 h. The target is a peak of 6 mg/L and a trough of 0.5 mg/L. Assuming rapid IV doses and first-order elimination, what dosing interval τ lets the level fall from the peak to the trough? Round to one decimal place.

t½ = 4 hCpeak = 6 mg/LCtrough = 0.5 mg/L
τ = h

Answer key

  1. 1. C = 3.789 mg/L
  2. 2. LD = 997.5 mg
  3. 3. t½ = 2 h
  4. 4. t½ = 7.01 h
  5. 5. t = 19.93 h
  6. 6. τ = 14.3 h

Full step-by-step solutions: practise this topic on examproblems.com.