Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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Name: ____________________   Date: ____________

1.Easy
110100t (h)C (mg/L)25 mg/L11 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the vancomycin level is 25 mg/L. The half-life is 8 h, and the drug is eliminated by first-order kinetics. What is the level C 11 h later?

C₀ = 25 mg/Lt½ = 8 ht = 11 h
C = mg/L
2.Easy
110100t (h)CC₀t½ = 8 hC₀/2

Practice exercise (made-up values, not clinical guidance). In a patient, vancomycin has an elimination half-life of 8 h. Find the elimination rate constant k in h⁻¹.

t½ = 8 h
k = h⁻¹
3.Medium
110100t (h)C (mg/L)C₀ = 12 mg/Lt½ = 2.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 210 mg of tobramycin. The level back-extrapolated to time zero is 12 mg/L and the half-life is 2.5 h. Find the volume of distribution Vd.

D = 210 mgC₀ = 12 mg/Lt½ = 2.5 h
Vd = L
4.Medium
110100t (h)C (mg/L)C₀ = 10 mg/Lt½ = 3 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 160 mg of tobramycin. The level back-extrapolated to time zero is 10 mg/L and the half-life is 3 h. Find the volume of distribution Vd.

D = 160 mgC₀ = 10 mg/Lt½ = 3 h
Vd = L
5.Hard
93 kg45 · womanSCr 2 mg/dLCrCl → τ = ? h

Practice exercise (made-up values, not clinical guidance). A 45-year-old woman weighs 93 kg and has a serum creatinine of 2 mg/dL (177 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual tobramycin regimen is 120 mg every 8 h for a creatinine clearance of 100 mL/min. Keeping the dose, the interval is lengthened in proportion to the fall in clearance. Find the new dosing interval τ. Round to one decimal place.

45 years93 kgwomanSCr = 2 mg/dL120 mg q8hCrCl normal 100 mL/min
τ = h
6.Hard
t (h)C (mg/L)Css​t = ?90%

Practice exercise (made-up values, not clinical guidance). A theophylline infusion is started without a loading dose. The half-life in this patient is 8 h. How long t does it take to reach 90% of the steady-state level?

t½ = 8 h90% Css
t = h

Answer key

  1. 1. C = 9.639 mg/L
  2. 2. k = 0.08664 h⁻¹
  3. 3. Vd = 17.5 L
  4. 4. Vd = 16 L
  5. 5. τ = 15.3 h
  6. 6. t = 26.58 h

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