Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
t/t½C/Css (%)100%2.5f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives lidocaine as a constant IV infusion without a loading dose. The half-life is 1.5 h. What percentage f of the steady-state level has been reached after 3.75 h?

t½ = 1.5 ht = 3.75 h
f = %
2.Easy
110100t (h)CC₀t½ = ?C₀/2

Practice exercise (made-up values, not clinical guidance). The elimination rate constant of digoxin in a patient is 0.0144 h⁻¹. Find the half-life t½.

k = 0.0144 h⁻¹
t½ = h
3.Medium
110t (h)C (mg/L)C₀ = 8 mg/Lt½ = 3 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 170 mg of tobramycin. The level back-extrapolated to time zero is 8 mg/L and the half-life is 3 h. Find the volume of distribution Vd.

D = 170 mgC₀ = 8 mg/Lt½ = 3 h
Vd = L
4.Medium
110100t (h)C (mg/L)1 h35 mg/L13 h8.8 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of vancomycin, the level is 35 mg/L at 1 h and 8.8 mg/L at 13 h. Assume first-order elimination. Find the half-life t½.

C1 = 35 mg/L (1 h)C2 = 8.8 mg/L (13 h)
t½ = h
5.Hard
Vd = 0.7 L/kg12 → 20 mg/LLD = ? mg61 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). A 61 kg patient has a phenytoin level of 12 mg/L; the target is 20 mg/L. The drug is given intravenously as phenytoin sodium (S = 0.92), and the volume of distribution is 0.7 L/kg. What extra loading dose LD raises the level to the target?

61 kgVd = 0.7 L/kgC = 12 → 20 mg/LS = 0.92
LD = mg
6.Hard
VCss,avg​ = ?450 mg · q8hCL = 0.05 L/kg/h56 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 56 kg patient takes oral aminophylline (S = 0.8, F = 1) every 8 h. The theophylline clearance is 0.05 L/kg/h. Each dose is 450 mg of aminophylline. Find the average steady-state level Css,avg.

CL = 0.05 L/kg/hτ = 8 hS = 0.8F = 156 kgD = 450 mg
Css,avg = mg/L

Answer key

  1. 1. f = 82.32 %
  2. 2. t½ = 48.14 h
  3. 3. Vd = 21.25 L
  4. 4. t½ = 6.025 h
  5. 5. LD = 371.3 mg
  6. 6. Css,avg = 16.07 mg/L

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