Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
t/t½C/Css (%)100%597%

Practice exercise (made-up values, not clinical guidance). A patient starts regular doses of digoxin, which has a half-life of 36 h. Using the rule that steady state is reached after about five half-lives, after how many hours tss is steady state reached?

t½ = 36 h
tss = h
2.Easy
110100t (h)CC₀t½ = 6 hC₀/2

Practice exercise (made-up values, not clinical guidance). In a patient, vancomycin has an elimination half-life of 6 h. Find the elimination rate constant k in h⁻¹.

t½ = 6 h
k = h⁻¹
3.Medium
VCss​ = 25 mg/LR = ? mg/hCL = 70 mL/min

Practice exercise (made-up values, not clinical guidance). Vancomycin is given as a continuous infusion to a patient whose vancomycin clearance is 70 mL/min. What infusion rate R in mg/h gives a steady-state level of 25 mg/L?

CL = 70 mL/minCss = 25 mg/L
R = mg/h
4.Medium
VCss​ = 10 mg/LR = ? mg/hCL = 0.045 L/kg/h60 kg

Practice exercise (made-up values, not clinical guidance). A 60 kg patient receives a theophylline infusion. The clearance is 0.045 L/kg/h. What infusion rate R in mg/h gives a steady-state level of 10 mg/L?

60 kgCL = 0.045 L/kg/hCss = 10 mg/L
R = mg/h
5.Hard
Vd = 0.25 L/kg1 → 7 mg/LD = ? mg52 kg

Practice exercise (made-up values, not clinical guidance). A 52 kg patient on regular gentamicin doses is at steady state. The target is a peak of 7 mg/L and a trough of 1 mg/L, and the volume of distribution is 0.25 L/kg. Assuming rapid IV doses, what dose D raises the level from the trough to the peak?

52 kgVd = 0.25 L/kgCpeak = 7 mg/LCtrough = 1 mg/L
D = mg
6.Hard
VCss,avg​ = 15 mg/LD = ? mg · q12hCL = 0.045 L/kg/h53 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 53 kg patient takes oral aminophylline (S = 0.8, F = 1) every 12 h. The theophylline clearance is 0.045 L/kg/h. What dose D in mg gives an average steady-state level of 15 mg/L?

CL = 0.045 L/kg/hτ = 12 hS = 0.8F = 153 kgCss,avg = 15 mg/L
D = mg

Answer key

  1. 1. tss = 180 h
  2. 2. k = 0.1155 h⁻¹
  3. 3. R = 105 mg/h
  4. 4. R = 27 mg/h
  5. 5. D = 78 mg
  6. 6. D = 536.6 mg

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