Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
110100t (h)CC₀t½ = ?C₀/2

Practice exercise (made-up values, not clinical guidance). The elimination rate constant of tobramycin in a patient is 0.231 h⁻¹. Find the half-life t½.

k = 0.231 h⁻¹
t½ = h
2.Easy
t/t½C/Css (%)100%3.5f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives lidocaine as a constant IV infusion without a loading dose. The half-life is 2 h. What percentage f of the steady-state level has been reached after 7 h?

t½ = 2 ht = 7 h
f = %
3.Medium
Vd = 0.5 L/kgC = 10 mg/LLD = ? mg100 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 100 kg patient is to be loaded intravenously with aminophylline to reach a theophylline level of 10 mg/L. The volume of distribution is 0.5 L/kg and the salt factor is S = 0.8. Find the loading dose LD of aminophylline in mg.

100 kgVd = 0.5 L/kgC = 10 mg/LS = 0.8
LD = mg
4.Medium
VCss​ = 4 mg/LR = ? mg/minCL = 800 mL/min

Practice exercise (made-up values, not clinical guidance). A patient has a lidocaine clearance of 800 mL/min. What infusion rate R in mg/min keeps the steady-state level at 4 mg/L?

CL = 800 mL/minCss = 4 mg/L
R = mg/min
5.Hard
Vd = 0.7 L/kg7.5 → 15 mg/LLD = ? mg67 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). A 67 kg patient has a phenytoin level of 7.5 mg/L; the target is 15 mg/L. The drug is given intravenously as phenytoin sodium (S = 0.92), and the volume of distribution is 0.7 L/kg. What extra loading dose LD raises the level to the target?

67 kgVd = 0.7 L/kgC = 7.5 → 15 mg/LS = 0.92
LD = mg
6.Hard
VCss,avg​ = ?250 mg · q8hCL = 0.03 L/kg/h57 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 57 kg patient takes oral aminophylline (S = 0.8, F = 1) every 8 h. The theophylline clearance is 0.03 L/kg/h. Each dose is 250 mg of aminophylline. Find the average steady-state level Css,avg.

CL = 0.03 L/kg/hτ = 8 hS = 0.8F = 157 kgD = 250 mg
Css,avg = mg/L

Answer key

  1. 1. t½ = 3.001 h
  2. 2. f = 91.16 %
  3. 3. LD = 625 mg
  4. 4. R = 3.2 mg/min
  5. 5. LD = 382.3 mg
  6. 6. Css,avg = 14.62 mg/L

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