Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
110100t (h)CC₀t½ = 1.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). In a patient, lidocaine has an elimination half-life of 1.5 h. Find the elimination rate constant k in h⁻¹.

t½ = 1.5 h
k = h⁻¹
2.Easy
Vd = 0.3 L/kgC = 8 mg/LLD = ?107 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 107 kg needs a loading dose of tobramycin to reach a level of 8 mg/L straight away. The volume of distribution is 0.3 L/kg. Find the loading dose LD in mg.

107 kgVd = 0.3 L/kgC = 8 mg/L
LD = mg
3.Medium
110100t (h)C (mg/L)C₀ = 10 mg/Lt½ = 3.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 240 mg of gentamicin. The level back-extrapolated to time zero is 10 mg/L and the half-life is 3.5 h. Find the clearance CL in L/h.

D = 240 mgC₀ = 10 mg/Lt½ = 3.5 h
CL = L/h
4.Medium
110t (h)C (mg/L)C₀ = 8 mg/Lt½ = 2 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 190 mg of tobramycin. The level back-extrapolated to time zero is 8 mg/L and the half-life is 2 h. Find the volume of distribution Vd.

D = 190 mgC₀ = 8 mg/Lt½ = 2 h
Vd = L
5.Hard
Vd = 0.25 L/kg0.5 → 7 mg/LD = ? mg52 kg

Practice exercise (made-up values, not clinical guidance). A 52 kg patient on regular tobramycin doses is at steady state. The target is a peak of 7 mg/L and a trough of 0.5 mg/L, and the volume of distribution is 0.25 L/kg. Assuming rapid IV doses, what dose D raises the level from the trough to the peak?

52 kgVd = 0.25 L/kgCpeak = 7 mg/LCtrough = 0.5 mg/L
D = mg
6.Hard
Vd = 0.5 L/kg7.2 → 12 mg/LLD = ? mg63 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 63 kg patient has a theophylline level of 7.2 mg/L; the target is 12 mg/L. The drug is given intravenously as aminophylline (S = 0.8), and the volume of distribution is 0.5 L/kg. What extra loading dose LD raises the level to the target?

63 kgVd = 0.5 L/kgC = 7.2 → 12 mg/LS = 0.8
LD = mg

Answer key

  1. 1. k = 0.4621 h⁻¹
  2. 2. LD = 256.8 mg
  3. 3. CL = 4.753 L/h
  4. 4. Vd = 23.75 L
  5. 5. D = 84.5 mg
  6. 6. LD = 189 mg

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