Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
110t (h)C (mg/L)6 mg/L1 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the tobramycin level is 6 mg/L. The half-life is 2.5 h, and the drug is eliminated by first-order kinetics. What is the level C 1 h later?

C₀ = 6 mg/Lt½ = 2.5 ht = 1 h
C = mg/L
2.Easy
Vd = 0.25 L/kgC = 10 mg/LLD = ?58 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 58 kg needs a loading dose of gentamicin to reach a level of 10 mg/L straight away. The volume of distribution is 0.25 L/kg. Find the loading dose LD in mg.

58 kgVd = 0.25 L/kgC = 10 mg/L
LD = mg
3.Medium
110t (h)C (mg/L)2 h6 mg/L5 h3 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of tobramycin, the level is 6 mg/L at 2 h and 3 mg/L at 5 h. Assume first-order elimination. Find the half-life t½.

C1 = 6 mg/L (2 h)C2 = 3 mg/L (5 h)
t½ = h
4.Medium
Vd = 0.7 L/kgC = 15 mg/LLD = ? mg85 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). An 85 kg patient is to be loaded intravenously with phenytoin sodium to reach a phenytoin level of 15 mg/L. The volume of distribution is 0.7 L/kg and the salt factor is S = 0.92. Find the loading dose LD of phenytoin sodium in mg.

85 kgVd = 0.7 L/kgC = 15 mg/LS = 0.92
LD = mg
5.Hard
t (h)C (mg/L)Css​t = ?90%

Practice exercise (made-up values, not clinical guidance). A theophylline infusion is started without a loading dose. The half-life in this patient is 9 h. How long t does it take to reach 90% of the steady-state level?

t½ = 9 h90% Css
t = h
6.Hard
Vd = 7 L/kg0.3 → 1 mcg/LLD = ? mcg83 kg · S = 1 · F = 0.7

Practice exercise (made-up values, not clinical guidance). An 83 kg patient has a digoxin level of 0.3 mcg/L; the target is 1 mcg/L. The volume of distribution is 7 L/kg and the tablets have F = 0.7. What extra loading dose LD raises the level to the target?

83 kgVd = 7 L/kgC = 0.3 → 1 mcg/LF = 0.7
LD = mcg

Answer key

  1. 1. C = 4.547 mg/L
  2. 2. LD = 145 mg
  3. 3. t½ = 3 h
  4. 4. LD = 970.1 mg
  5. 5. t = 29.9 h
  6. 6. LD = 581 mcg

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