Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
t/t½C/Css (%)100%3.5f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives vancomycin as a constant IV infusion without a loading dose. The half-life is 12 h. What percentage f of the steady-state level has been reached after 42 h?

t½ = 12 ht = 42 h
f = %
2.Easy
Vd = 0.7 L/kgC = 25 mg/LLD = ?67 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 67 kg needs a loading dose of vancomycin to reach a level of 25 mg/L straight away. The volume of distribution is 0.7 L/kg. Find the loading dose LD in mg.

67 kgVd = 0.7 L/kgC = 25 mg/L
LD = mg
3.Medium
110t (h)C (mg/L)C₀ = 8 mg/Lt½ = 2.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 220 mg of gentamicin. The level back-extrapolated to time zero is 8 mg/L and the half-life is 2.5 h. Find the clearance CL in L/h.

D = 220 mgC₀ = 8 mg/Lt½ = 2.5 h
CL = L/h
4.Medium
VCss​ = 25 mg/LR = ? mg/hCL = 3.5 L/h

Practice exercise (made-up values, not clinical guidance). Vancomycin is given as a continuous infusion to a patient whose vancomycin clearance is 3.5 L/h. What infusion rate R in mg/h gives a steady-state level of 25 mg/L?

CL = 3.5 L/hCss = 25 mg/L
R = mg/h
5.Hard
t (h)C (mg/L)Css​2 hC = ?

Practice exercise (made-up values, not clinical guidance). A theophylline infusion runs at 37.5 mg/h with no loading dose. The patient's clearance is 2.5 L/h and the half-life is 9 h. What is the level C after 2 h?

R = 37.5 mg/hCL = 2.5 L/ht½ = 9 ht = 2 h
C = mg/L
6.Hard
VCss,avg​ = 15 mg/LD = ? mg · q8hCL = 0.045 L/kg/h76 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 76 kg patient takes oral aminophylline (S = 0.8, F = 1) every 8 h. The theophylline clearance is 0.045 L/kg/h. What dose D in mg gives an average steady-state level of 15 mg/L?

CL = 0.045 L/kg/hτ = 8 hS = 0.8F = 176 kgCss,avg = 15 mg/L
D = mg

Answer key

  1. 1. f = 91.16 %
  2. 2. LD = 1173 mg
  3. 3. CL = 7.625 L/h
  4. 4. R = 87.5 mg/h
  5. 5. C = 2.141 mg/L
  6. 6. D = 513 mg

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