Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
t/t½C/Css (%)100%2.5f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives aminophylline as a constant IV infusion without a loading dose. The half-life is 6 h. What percentage f of the steady-state level has been reached after 15 h?

t½ = 6 ht = 15 h
f = %
2.Easy
0.1110100t (h)C (mg/L)9 mg/L11 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the gentamicin level is 9 mg/L. The half-life is 3 h, and the drug is eliminated by first-order kinetics. What is the level C 11 h later?

C₀ = 9 mg/Lt½ = 3 ht = 11 h
C = mg/L
3.Medium
110t (h)C (mg/L)2 h6 mg/L5 h2.1 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of tobramycin, the level is 6 mg/L at 2 h and 2.1 mg/L at 5 h. Assume first-order elimination. Find the elimination rate constant k.

C1 = 6 mg/L (2 h)C2 = 2.1 mg/L (5 h)
k = h⁻¹
4.Medium
Vd = 7 L/kgC = 0.8 mcg/LLD = ? mcg68 kg · S = 1 · F = 0.7

Practice exercise (made-up values, not clinical guidance). A 68 kg patient is to be loaded with digoxin tablets to reach a level of 0.8 mcg/L. The volume of distribution is 7 L/kg and the tablets have a bioavailability F = 0.7. Find the total oral loading dose LD in mcg.

68 kgVd = 7 L/kgC = 0.8 mcg/LF = 0.7
LD = mcg
5.Hard
Vd = 0.3 L/kg0.5 → 8 mg/LD = ? mg53 kg

Practice exercise (made-up values, not clinical guidance). A 53 kg patient on regular tobramycin doses is at steady state. The target is a peak of 8 mg/L and a trough of 0.5 mg/L, and the volume of distribution is 0.3 L/kg. Assuming rapid IV doses, what dose D raises the level from the trough to the peak?

53 kgVd = 0.3 L/kgCpeak = 8 mg/LCtrough = 0.5 mg/L
D = mg
6.Hard
VCss,avg​ = 12 mg/LD = ? mg · q8hCL = 0.03 L/kg/h78 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 78 kg patient takes oral aminophylline (S = 0.8, F = 1) every 8 h. The theophylline clearance is 0.03 L/kg/h. What dose D in mg gives an average steady-state level of 12 mg/L?

CL = 0.03 L/kg/hτ = 8 hS = 0.8F = 178 kgCss,avg = 12 mg/L
D = mg

Answer key

  1. 1. f = 82.32 %
  2. 2. C = 0.7087 mg/L
  3. 3. k = 0.3499 h⁻¹
  4. 4. LD = 544 mcg
  5. 5. D = 119.2 mg
  6. 6. D = 280.8 mg

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