Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
110100t (h)CC₀t½ = 8 hC₀/2

Practice exercise (made-up values, not clinical guidance). In a patient, theophylline has an elimination half-life of 8 h. Find the elimination rate constant k in h⁻¹.

t½ = 8 h
k = h⁻¹
2.Easy
110100t (h)C (mg/L)35 mg/L19 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the vancomycin level is 35 mg/L. The half-life is 6 h, and the drug is eliminated by first-order kinetics. What is the level C 19 h later?

C₀ = 35 mg/Lt½ = 6 ht = 19 h
C = mg/L
3.Medium
110100t (h)C (mg/L)2 h10 mg/L7 h3.1 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of gentamicin, the level is 10 mg/L at 2 h and 3.1 mg/L at 7 h. Assume first-order elimination. Find the half-life t½.

C1 = 10 mg/L (2 h)C2 = 3.1 mg/L (7 h)
t½ = h
4.Medium
Vd = 7 L/kgC = 0.8 mcg/LLD = ? mcg97 kg · S = 1 · F = 0.7

Practice exercise (made-up values, not clinical guidance). A 97 kg patient is to be loaded with digoxin tablets to reach a level of 0.8 mcg/L. The volume of distribution is 7 L/kg and the tablets have a bioavailability F = 0.7. Find the total oral loading dose LD in mcg.

97 kgVd = 7 L/kgC = 0.8 mcg/LF = 0.7
LD = mcg
5.Hard
62 kg76 · womanSCr 1.5 mg/dLCrCl → D = ? mg

Practice exercise (made-up values, not clinical guidance). A 76-year-old woman weighs 62 kg and has a serum creatinine of 1.5 mg/dL (133 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual vancomycin dose is 1000 mg every 12 h for a creatinine clearance of 100 mL/min. Keeping the interval, the dose is reduced in proportion to the creatinine clearance. Find the adjusted dose D. Round to the nearest whole number.

76 years62 kgwomanSCr = 1.5 mg/dL1000 mg q12hCrCl normal 100 mL/min
D = mg
6.Hard
0.1110t (h)C (mg/L)Cpeak​ = 7τ = ?Ctrough​ = 0.5

Practice exercise (made-up values, not clinical guidance). A patient's tobramycin half-life is 3.5 h. The target is a peak of 7 mg/L and a trough of 0.5 mg/L. Assuming rapid IV doses and first-order elimination, what dosing interval τ lets the level fall from the peak to the trough? Round to one decimal place.

t½ = 3.5 hCpeak = 7 mg/LCtrough = 0.5 mg/L
τ = h

Answer key

  1. 1. k = 0.08664 h⁻¹
  2. 2. C = 3.898 mg/L
  3. 3. t½ = 2.959 h
  4. 4. LD = 776 mcg
  5. 5. D = 312 mg
  6. 6. τ = 13.3 h

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