Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
110100t (h)CC₀t½ = 2.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). In a patient, tobramycin has an elimination half-life of 2.5 h. Find the elimination rate constant k in h⁻¹.

t½ = 2.5 h
k = h⁻¹
2.Easy
0.1110t (h)C (mg/L)7 mg/L8 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the gentamicin level is 7 mg/L. The half-life is 2 h, and the drug is eliminated by first-order kinetics. What is the level C 8 h later?

C₀ = 7 mg/Lt½ = 2 ht = 8 h
C = mg/L
3.Medium
110t (h)C (mg/L)1 h7 mg/L5 h2.3 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of gentamicin, the level is 7 mg/L at 1 h and 2.3 mg/L at 5 h. Assume first-order elimination. Find the half-life t½.

C1 = 7 mg/L (1 h)C2 = 2.3 mg/L (5 h)
t½ = h
4.Medium
110t (h)C (mg/L)C₀ = 8 mg/Lt½ = 2.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 150 mg of tobramycin. The level back-extrapolated to time zero is 8 mg/L and the half-life is 2.5 h. Find the volume of distribution Vd.

D = 150 mgC₀ = 8 mg/Lt½ = 2.5 h
Vd = L
5.Hard
66 kg65 · manSCr 1.3 mg/dLCrCl → τ = ? h

Practice exercise (made-up values, not clinical guidance). A 65-year-old man weighs 66 kg and has a serum creatinine of 1.3 mg/dL (115 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual vancomycin regimen is 1000 mg every 12 h for a creatinine clearance of 100 mL/min. Keeping the dose, the interval is lengthened in proportion to the fall in clearance. Find the new dosing interval τ. Round to one decimal place.

65 years66 kgmanSCr = 1.3 mg/dL1000 mg q12hCrCl normal 100 mL/min
τ = h
6.Hard
VCss,avg​ = ?250 mg · q12hCL = 0.035 L/kg/h79 kg · S = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). A 79 kg patient takes oral theophylline (F = 1) every 12 h. The clearance is 0.035 L/kg/h. Each dose is 250 mg of theophylline. Find the average steady-state level Css,avg.

CL = 0.035 L/kg/hτ = 12 hS = 1F = 179 kgD = 250 mg
Css,avg = mg/L

Answer key

  1. 1. k = 0.2773 h⁻¹
  2. 2. C = 0.4375 mg/L
  3. 3. t½ = 2.491 h
  4. 4. Vd = 18.75 L
  5. 5. τ = 22.7 h
  6. 6. Css,avg = 7.535 mg/L

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