Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
110t (h)C (mg/L)8 mg/L4 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the gentamicin level is 8 mg/L. The half-life is 2.5 h, and the drug is eliminated by first-order kinetics. What is the level C 4 h later?

C₀ = 8 mg/Lt½ = 2.5 ht = 4 h
C = mg/L
2.Easy
10100t (h)C (mg/L)35 mg/L5 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the vancomycin level is 35 mg/L. The half-life is 12 h, and the drug is eliminated by first-order kinetics. What is the level C 5 h later?

C₀ = 35 mg/Lt½ = 12 ht = 5 h
C = mg/L
3.Medium
110t (h)C (mg/L)1 h8 mg/L7 h2 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of tobramycin, the level is 8 mg/L at 1 h and 2 mg/L at 7 h. Assume first-order elimination. Find the half-life t½.

C1 = 8 mg/L (1 h)C2 = 2 mg/L (7 h)
t½ = h
4.Medium
Vd = 0.7 L/kgC = 15 mg/LLD = ? mg58 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). A 58 kg patient is to be loaded intravenously with phenytoin sodium to reach a phenytoin level of 15 mg/L. The volume of distribution is 0.7 L/kg and the salt factor is S = 0.92. Find the loading dose LD of phenytoin sodium in mg.

58 kgVd = 0.7 L/kgC = 15 mg/LS = 0.92
LD = mg
5.Hard
68 kg84 · womanSCr 2.1 mg/dLfe​ = 0.7D = ? mcg

Practice exercise (made-up values, not clinical guidance). An 84-year-old woman weighs 68 kg and has a serum creatinine of 2.1 mg/dL (186 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual digoxin dose is 250 mcg for a creatinine clearance of 100 mL/min, and a fraction fe = 0.7 of the drug is excreted unchanged by the kidneys. Using the Dettli dose fraction Q = 1 − fe·(1 − CrCl/normal CrCl), find the adjusted dose D. Round to the nearest whole number.

84 years68 kgwomanSCr = 2.1 mg/dL250 mcgfe = 0.7CrCl normal 100 mL/min
D = mcg
6.Hard
Vd = 0.5 L/kg4 → 10 mg/LLD = ? mg75 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 75 kg patient has a theophylline level of 4 mg/L; the target is 10 mg/L. The drug is given intravenously as aminophylline (S = 0.8), and the volume of distribution is 0.5 L/kg. What extra loading dose LD raises the level to the target?

75 kgVd = 0.5 L/kgC = 4 → 10 mg/LS = 0.8
LD = mg

Answer key

  1. 1. C = 2.639 mg/L
  2. 2. C = 26.22 mg/L
  3. 3. t½ = 3 h
  4. 4. LD = 662 mg
  5. 5. D = 112 mcg
  6. 6. LD = 281.3 mg

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