Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
t/t½C/Css (%)100%3.5f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives aminophylline as a constant IV infusion without a loading dose. The half-life is 6 h. What percentage f of the steady-state level has been reached after 21 h?

t½ = 6 ht = 21 h
f = %
2.Easy
110100t (h)CC₀t½ = 36 hC₀/2

Practice exercise (made-up values, not clinical guidance). In a patient, digoxin has an elimination half-life of 36 h. Find the elimination rate constant k in h⁻¹.

t½ = 36 h
k = h⁻¹
3.Medium
110100t (h)C (mg/L)C₀ = 10 mg/Lt½ = 2 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 220 mg of tobramycin. The level back-extrapolated to time zero is 10 mg/L and the half-life is 2 h. Find the clearance CL in L/h.

D = 220 mgC₀ = 10 mg/Lt½ = 2 h
CL = L/h
4.Medium
110100t (h)C (mg/L)C₀ = 10 mg/Lt½ = 2.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 260 mg of tobramycin. The level back-extrapolated to time zero is 10 mg/L and the half-life is 2.5 h. Find the volume of distribution Vd.

D = 260 mgC₀ = 10 mg/Lt½ = 2.5 h
Vd = L
5.Hard
t (h)C (mg/L)Css​11 hC = ?

Practice exercise (made-up values, not clinical guidance). A theophylline infusion runs at 30 mg/h with no loading dose. The patient's clearance is 2.5 L/h and the half-life is 8 h. What is the level C after 11 h?

R = 30 mg/hCL = 2.5 L/ht½ = 8 ht = 11 h
C = mg/L
6.Hard
VCss,avg​ = ?200 mg · q8hCL = 0.045 L/kg/h80 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). An 80 kg patient takes oral aminophylline (S = 0.8, F = 1) every 8 h. The theophylline clearance is 0.045 L/kg/h. Each dose is 200 mg of aminophylline. Find the average steady-state level Css,avg.

CL = 0.045 L/kg/hτ = 8 hS = 0.8F = 180 kgD = 200 mg
Css,avg = mg/L

Answer key

  1. 1. f = 91.16 %
  2. 2. k = 0.01925 h⁻¹
  3. 3. CL = 7.625 L/h
  4. 4. Vd = 26 L
  5. 5. C = 7.373 mg/L
  6. 6. Css,avg = 5.556 mg/L

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