Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
Vd = 0.3 L/kgC = 8 mg/LLD = ?86 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 86 kg needs a loading dose of tobramycin to reach a level of 8 mg/L straight away. The volume of distribution is 0.3 L/kg. Find the loading dose LD in mg.

86 kgVd = 0.3 L/kgC = 8 mg/L
LD = mg
2.Easy
Vd = 0.25 L/kgC = 8 mg/LLD = ?64 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 64 kg needs a loading dose of gentamicin to reach a level of 8 mg/L straight away. The volume of distribution is 0.25 L/kg. Find the loading dose LD in mg.

64 kgVd = 0.25 L/kgC = 8 mg/L
LD = mg
3.Medium
10100t (h)C (mg/L)1 h35 mg/L9 h13.9 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of vancomycin, the level is 35 mg/L at 1 h and 13.9 mg/L at 9 h. Assume first-order elimination. Find the elimination rate constant k.

C1 = 35 mg/L (1 h)C2 = 13.9 mg/L (9 h)
k = h⁻¹
4.Medium
Vd = 0.7 L/kgC = 15 mg/LLD = ? mg93 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). A 93 kg patient is to be loaded intravenously with phenytoin sodium to reach a phenytoin level of 15 mg/L. The volume of distribution is 0.7 L/kg and the salt factor is S = 0.92. Find the loading dose LD of phenytoin sodium in mg.

93 kgVd = 0.7 L/kgC = 15 mg/LS = 0.92
LD = mg
5.Hard
VCss,avg​ = 10 mg/LD = ? mg · q8hCL = 0.035 L/kg/h96 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 96 kg patient takes oral aminophylline (S = 0.8, F = 1) every 8 h. The theophylline clearance is 0.035 L/kg/h. What dose D in mg gives an average steady-state level of 10 mg/L?

CL = 0.035 L/kg/hτ = 8 hS = 0.8F = 196 kgCss,avg = 10 mg/L
D = mg
6.Hard
VCss,avg​ = 10 mg/LD = ? mg · q12hCL = 0.045 L/kg/h93 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 93 kg patient takes oral aminophylline (S = 0.8, F = 1) every 12 h. The theophylline clearance is 0.045 L/kg/h. What dose D in mg gives an average steady-state level of 10 mg/L?

CL = 0.045 L/kg/hτ = 12 hS = 0.8F = 193 kgCss,avg = 10 mg/L
D = mg

Answer key

  1. 1. LD = 206.4 mg
  2. 2. LD = 128 mg
  3. 3. k = 0.1154 h⁻¹
  4. 4. LD = 1061 mg
  5. 5. D = 336 mg
  6. 6. D = 627.7 mg

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