Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
110100t (h)C (mg/L)30 mg/L33 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the vancomycin level is 30 mg/L. The half-life is 12 h, and the drug is eliminated by first-order kinetics. What is the level C 33 h later?

C₀ = 30 mg/Lt½ = 12 ht = 33 h
C = mg/L
2.Easy
t/t½C/Css (%)100%597%

Practice exercise (made-up values, not clinical guidance). A patient starts regular doses of gentamicin, which has a half-life of 2.5 h. Using the rule that steady state is reached after about five half-lives, after how many hours tss is steady state reached?

t½ = 2.5 h
tss = h
3.Medium
VCss​ = 2.5 mg/LR = ? mg/minCL = 750 mL/min

Practice exercise (made-up values, not clinical guidance). A patient has a lidocaine clearance of 750 mL/min. What infusion rate R in mg/min keeps the steady-state level at 2.5 mg/L?

CL = 750 mL/minCss = 2.5 mg/L
R = mg/min
4.Medium
Vd = 0.7 L/kgC = 20 mg/LLD = ? mg54 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). A 54 kg patient is to be loaded intravenously with phenytoin sodium to reach a phenytoin level of 20 mg/L. The volume of distribution is 0.7 L/kg and the salt factor is S = 0.92. Find the loading dose LD of phenytoin sodium in mg.

54 kgVd = 0.7 L/kgC = 20 mg/LS = 0.92
LD = mg
5.Hard
t (h)C (mg/L)Css​t = ?90%

Practice exercise (made-up values, not clinical guidance). A theophylline infusion is started without a loading dose. The half-life in this patient is 8 h. How long t does it take to reach 90% of the steady-state level?

t½ = 8 h90% Css
t = h
6.Hard
0.1110t (h)C (mg/L)Cpeak​ = 6τ = ?Ctrough​ = 0.5

Practice exercise (made-up values, not clinical guidance). A patient's tobramycin half-life is 2.5 h. The target is a peak of 6 mg/L and a trough of 0.5 mg/L. Assuming rapid IV doses and first-order elimination, what dosing interval τ lets the level fall from the peak to the trough? Round to one decimal place.

t½ = 2.5 hCpeak = 6 mg/LCtrough = 0.5 mg/L
τ = h

Answer key

  1. 1. C = 4.46 mg/L
  2. 2. tss = 12.5 h
  3. 3. R = 1.875 mg/min
  4. 4. LD = 821.7 mg
  5. 5. t = 26.58 h
  6. 6. τ = 9 h

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