Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
0.1110t (h)C (mg/L)6 mg/L9.5 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the tobramycin level is 6 mg/L. The half-life is 2.5 h, and the drug is eliminated by first-order kinetics. What is the level C 9.5 h later?

C₀ = 6 mg/Lt½ = 2.5 ht = 9.5 h
C = mg/L
2.Easy
t/t½C/Css (%)100%597%

Practice exercise (made-up values, not clinical guidance). A patient starts regular doses of theophylline, which has a half-life of 9 h. Using the rule that steady state is reached after about five half-lives, after how many hours tss is steady state reached?

t½ = 9 h
tss = h
3.Medium
Vd = 0.5 L/kgC = 10 mg/LLD = ? mg54 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 54 kg patient is to be loaded intravenously with aminophylline to reach a theophylline level of 10 mg/L. The volume of distribution is 0.5 L/kg and the salt factor is S = 0.8. Find the loading dose LD of aminophylline in mg.

54 kgVd = 0.5 L/kgC = 10 mg/LS = 0.8
LD = mg
4.Medium
Vd = 7 L/kgC = 1 mcg/LLD = ? mcg84 kg · S = 1 · F = 0.7

Practice exercise (made-up values, not clinical guidance). An 84 kg patient is to be loaded with digoxin tablets to reach a level of 1 mcg/L. The volume of distribution is 7 L/kg and the tablets have a bioavailability F = 0.7. Find the total oral loading dose LD in mcg.

84 kgVd = 7 L/kgC = 1 mcg/LF = 0.7
LD = mcg
5.Hard
0.1110t (h)C (mg/L)Cpeak​ = 8τ = ?Ctrough​ = 0.5

Practice exercise (made-up values, not clinical guidance). A patient's gentamicin half-life is 4 h. The target is a peak of 8 mg/L and a trough of 0.5 mg/L. Assuming rapid IV doses and first-order elimination, what dosing interval τ lets the level fall from the peak to the trough? Round to one decimal place.

t½ = 4 hCpeak = 8 mg/LCtrough = 0.5 mg/L
τ = h
6.Hard
VCss,avg​ = ?250 mg · q8hCL = 0.03 L/kg/h70 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 70 kg patient takes oral aminophylline (S = 0.8, F = 1) every 8 h. The theophylline clearance is 0.03 L/kg/h. Each dose is 250 mg of aminophylline. Find the average steady-state level Css,avg.

CL = 0.03 L/kg/hτ = 8 hS = 0.8F = 170 kgD = 250 mg
Css,avg = mg/L

Answer key

  1. 1. C = 0.4308 mg/L
  2. 2. tss = 45 h
  3. 3. LD = 337.5 mg
  4. 4. LD = 840 mcg
  5. 5. τ = 16 h
  6. 6. Css,avg = 11.9 mg/L

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