Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
t/t½C/Css (%)100%597%

Practice exercise (made-up values, not clinical guidance). A patient starts regular doses of phenobarbital, which has a half-life of 80 h. Using the rule that steady state is reached after about five half-lives, after how many hours tss is steady state reached?

t½ = 80 h
tss = h
2.Easy
Vd = 0.7 L/kgC = 30 mg/LLD = ?85 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 85 kg needs a loading dose of vancomycin to reach a level of 30 mg/L straight away. The volume of distribution is 0.7 L/kg. Find the loading dose LD in mg.

85 kgVd = 0.7 L/kgC = 30 mg/L
LD = mg
3.Medium
VCss​ = 20 mg/LR = ? mg/hCL = 85 mL/min

Practice exercise (made-up values, not clinical guidance). Vancomycin is given as a continuous infusion to a patient whose vancomycin clearance is 85 mL/min. What infusion rate R in mg/h gives a steady-state level of 20 mg/L?

CL = 85 mL/minCss = 20 mg/L
R = mg/h
4.Medium
VCss​ = 15 mg/LR = ? mg/hCL = 0.03 L/kg/h73 kg

Practice exercise (made-up values, not clinical guidance). A 73 kg patient receives a theophylline infusion. The clearance is 0.03 L/kg/h. What infusion rate R in mg/h gives a steady-state level of 15 mg/L?

73 kgCL = 0.03 L/kg/hCss = 15 mg/L
R = mg/h
5.Hard
t (h)C (mg/L)Css​21 hC = ?

Practice exercise (made-up values, not clinical guidance). A vancomycin infusion runs at 100 mg/h with no loading dose. The patient's clearance is 5 L/h and the half-life is 8 h. What is the level C after 21 h?

R = 100 mg/hCL = 5 L/ht½ = 8 ht = 21 h
C = mg/L
6.Hard
0.1110t (h)C (mg/L)Cpeak​ = 6τ = ?Ctrough​ = 1

Practice exercise (made-up values, not clinical guidance). A patient's tobramycin half-life is 3 h. The target is a peak of 6 mg/L and a trough of 1 mg/L. Assuming rapid IV doses and first-order elimination, what dosing interval τ lets the level fall from the peak to the trough? Round to one decimal place.

t½ = 3 hCpeak = 6 mg/LCtrough = 1 mg/L
τ = h

Answer key

  1. 1. tss = 400 h
  2. 2. LD = 1785 mg
  3. 3. R = 102 mg/h
  4. 4. R = 32.85 mg/h
  5. 5. C = 16.76 mg/L
  6. 6. τ = 7.8 h

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