Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
110100t (h)CC₀t½ = 1.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). In a patient, lidocaine has an elimination half-life of 1.5 h. Find the elimination rate constant k in h⁻¹.

t½ = 1.5 h
k = h⁻¹
2.Easy
0.1110t (h)C (mg/L)8 mg/L10.5 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the gentamicin level is 8 mg/L. The half-life is 3.5 h, and the drug is eliminated by first-order kinetics. What is the level C 10.5 h later?

C₀ = 8 mg/Lt½ = 3.5 ht = 10.5 h
C = mg/L
3.Medium
110t (h)C (mg/L)C₀ = 8 mg/Lt½ = 3 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 190 mg of gentamicin. The level back-extrapolated to time zero is 8 mg/L and the half-life is 3 h. Find the clearance CL in L/h.

D = 190 mgC₀ = 8 mg/Lt½ = 3 h
CL = L/h
4.Medium
Vd = 7 L/kgC = 0.8 mcg/LLD = ? mcg50 kg · S = 1 · F = 0.7

Practice exercise (made-up values, not clinical guidance). A 50 kg patient is to be loaded with digoxin tablets to reach a level of 0.8 mcg/L. The volume of distribution is 7 L/kg and the tablets have a bioavailability F = 0.7. Find the total oral loading dose LD in mcg.

50 kgVd = 7 L/kgC = 0.8 mcg/LF = 0.7
LD = mcg
5.Hard
Vd = 0.7 L/kg9 → 15 mg/LLD = ? mg98 kg · S = 0.92 · F = 1

Practice exercise (made-up values, not clinical guidance). A 98 kg patient has a phenytoin level of 9 mg/L; the target is 15 mg/L. The drug is given intravenously as phenytoin sodium (S = 0.92), and the volume of distribution is 0.7 L/kg. What extra loading dose LD raises the level to the target?

98 kgVd = 0.7 L/kgC = 9 → 15 mg/LS = 0.92
LD = mg
6.Hard
VCss,avg​ = 20 mg/LD = ? mg · q12hCL = 3.5 L/hS = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). A patient receives vancomycin IV every 12 h; the vancomycin clearance is 3.5 L/h. What dose D in mg gives an average steady-state level of 20 mg/L?

CL = 3.5 L/hτ = 12 hS = 1F = 1Css,avg = 20 mg/L
D = mg

Answer key

  1. 1. k = 0.4621 h⁻¹
  2. 2. C = 1 mg/L
  3. 3. CL = 5.487 L/h
  4. 4. LD = 400 mcg
  5. 5. LD = 447.4 mg
  6. 6. D = 840 mg

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