Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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Name: ____________________   Date: ____________

1.Easy
Vd = 0.7 L/kgC = 30 mg/LLD = ?54 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 54 kg needs a loading dose of vancomycin to reach a level of 30 mg/L straight away. The volume of distribution is 0.7 L/kg. Find the loading dose LD in mg.

54 kgVd = 0.7 L/kgC = 30 mg/L
LD = mg
2.Easy
110t (h)C (mg/L)6 mg/L3 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the tobramycin level is 6 mg/L. The half-life is 3 h, and the drug is eliminated by first-order kinetics. What is the level C 3 h later?

C₀ = 6 mg/Lt½ = 3 ht = 3 h
C = mg/L
3.Medium
110100t (h)C (mg/L)C₀ = 12 mg/Lt½ = 3.5 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 290 mg of gentamicin. The level back-extrapolated to time zero is 12 mg/L and the half-life is 3.5 h. Find the clearance CL in L/h.

D = 290 mgC₀ = 12 mg/Lt½ = 3.5 h
CL = L/h
4.Medium
VCss​ = 15 mg/LR = ? mg/h · S = 0.8CL = 0.04 L/kg/h52 kg

Practice exercise (made-up values, not clinical guidance). A 52 kg patient is to receive an aminophylline infusion (salt factor S = 0.8: 80% of aminophylline is theophylline). The theophylline clearance is 0.04 L/kg/h. What aminophylline infusion rate R in mg/h gives a steady-state theophylline level of 15 mg/L?

52 kgCL = 0.04 L/kg/hCss = 15 mg/LS = 0.8
R = mg/h
5.Hard
VCss,avg​ = 20 mg/LD = ? mg · q12hCL = 5 L/hS = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). A patient receives vancomycin IV every 12 h; the vancomycin clearance is 5 L/h. What dose D in mg gives an average steady-state level of 20 mg/L?

CL = 5 L/hτ = 12 hS = 1F = 1Css,avg = 20 mg/L
D = mg
6.Hard
VCss,avg​ = 12 mg/LD = ? mg · q8hCL = 0.04 L/kg/h51 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 51 kg patient takes oral aminophylline (S = 0.8, F = 1) every 8 h. The theophylline clearance is 0.04 L/kg/h. What dose D in mg gives an average steady-state level of 12 mg/L?

CL = 0.04 L/kg/hτ = 8 hS = 0.8F = 151 kgCss,avg = 12 mg/L
D = mg

Answer key

  1. 1. LD = 1134 mg
  2. 2. C = 3 mg/L
  3. 3. CL = 4.786 L/h
  4. 4. R = 39 mg/h
  5. 5. D = 1200 mg
  6. 6. D = 244.8 mg

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