Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
110t (h)C (mg/L)8 mg/L1.5 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the tobramycin level is 8 mg/L. The half-life is 3 h, and the drug is eliminated by first-order kinetics. What is the level C 1.5 h later?

C₀ = 8 mg/Lt½ = 3 ht = 1.5 h
C = mg/L
2.Easy
Vd = 0.3 L/kgC = 6 mg/LLD = ?68 kg

Practice exercise (made-up values, not clinical guidance). A patient who weighs 68 kg needs a loading dose of tobramycin to reach a level of 6 mg/L straight away. The volume of distribution is 0.3 L/kg. Find the loading dose LD in mg.

68 kgVd = 0.3 L/kgC = 6 mg/L
LD = mg
3.Medium
110100t (h)C (mg/L)C₀ = 12 mg/Lt½ = 3 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 270 mg of gentamicin. The level back-extrapolated to time zero is 12 mg/L and the half-life is 3 h. Find the volume of distribution Vd.

D = 270 mgC₀ = 12 mg/Lt½ = 3 h
Vd = L
4.Medium
VCss​ = 12 mg/LR = ? mg/h · S = 0.8CL = 0.04 L/kg/h72 kg

Practice exercise (made-up values, not clinical guidance). A 72 kg patient is to receive an aminophylline infusion (salt factor S = 0.8: 80% of aminophylline is theophylline). The theophylline clearance is 0.04 L/kg/h. What aminophylline infusion rate R in mg/h gives a steady-state theophylline level of 12 mg/L?

72 kgCL = 0.04 L/kg/hCss = 12 mg/LS = 0.8
R = mg/h
5.Hard
Vd = 7 L/kg0.2 → 0.8 mcg/LLD = ? mcg85 kg · S = 1 · F = 0.7

Practice exercise (made-up values, not clinical guidance). An 85 kg patient has a digoxin level of 0.2 mcg/L; the target is 0.8 mcg/L. The volume of distribution is 7 L/kg and the tablets have F = 0.7. What extra loading dose LD raises the level to the target?

85 kgVd = 7 L/kgC = 0.2 → 0.8 mcg/LF = 0.7
LD = mcg
6.Hard
VCss,avg​ = 10 mg/LD = ? mg · q8hCL = 0.045 L/kg/h89 kg · S = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). An 89 kg patient takes oral theophylline (F = 1) every 8 h. The clearance is 0.045 L/kg/h. What dose D in mg gives an average steady-state level of 10 mg/L?

CL = 0.045 L/kg/hτ = 8 hS = 1F = 189 kgCss,avg = 10 mg/L
D = mg

Answer key

  1. 1. C = 5.657 mg/L
  2. 2. LD = 122.4 mg
  3. 3. Vd = 22.5 L
  4. 4. R = 43.2 mg/h
  5. 5. LD = 510 mcg
  6. 6. D = 320.4 mg

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