Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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Name: ____________________   Date: ____________

1.Easy
110100t (h)CC₀t½ = 48 hC₀/2

Practice exercise (made-up values, not clinical guidance). In a patient, digoxin has an elimination half-life of 48 h. Find the elimination rate constant k in h⁻¹.

t½ = 48 h
k = h⁻¹
2.Easy
t/t½C/Css (%)100%4f = ?

Practice exercise (made-up values, not clinical guidance). A patient receives vancomycin as a constant IV infusion without a loading dose. The half-life is 12 h. What percentage f of the steady-state level has been reached after 48 h?

t½ = 12 ht = 48 h
f = %
3.Medium
110100t (h)C (mg/L)2 h9 mg/L7 h3.3 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of gentamicin, the level is 9 mg/L at 2 h and 3.3 mg/L at 7 h. Assume first-order elimination. Find the half-life t½.

C1 = 9 mg/L (2 h)C2 = 3.3 mg/L (7 h)
t½ = h
4.Medium
110100t (h)C (mg/L)1 h10 mg/L6 h3.1 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of tobramycin, the level is 10 mg/L at 1 h and 3.1 mg/L at 6 h. Assume first-order elimination. Find the elimination rate constant k.

C1 = 10 mg/L (1 h)C2 = 3.1 mg/L (6 h)
k = h⁻¹
5.Hard
VCss,avg​ = 10 mg/LD = ? mg · q8hCL = 0.035 L/kg/h53 kg · S = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). A 53 kg patient takes oral theophylline (F = 1) every 8 h. The clearance is 0.035 L/kg/h. What dose D in mg gives an average steady-state level of 10 mg/L?

CL = 0.035 L/kg/hτ = 8 hS = 1F = 153 kgCss,avg = 10 mg/L
D = mg
6.Hard
VCss,avg​ = 15 mg/LD = ? mg · q12hCL = 0.035 L/kg/h86 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). An 86 kg patient takes oral aminophylline (S = 0.8, F = 1) every 12 h. The theophylline clearance is 0.035 L/kg/h. What dose D in mg gives an average steady-state level of 15 mg/L?

CL = 0.035 L/kg/hτ = 12 hS = 0.8F = 186 kgCss,avg = 15 mg/L
D = mg

Answer key

  1. 1. k = 0.01444 h⁻¹
  2. 2. f = 93.75 %
  3. 3. t½ = 3.454 h
  4. 4. k = 0.2342 h⁻¹
  5. 5. D = 148.4 mg
  6. 6. D = 677.3 mg

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