Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
110100t (h)CC₀t½ = ?C₀/2

Practice exercise (made-up values, not clinical guidance). The elimination rate constant of tobramycin in a patient is 0.347 h⁻¹. Find the half-life t½.

k = 0.347 h⁻¹
t½ = h
2.Easy
110t (h)C (mg/L)6 mg/L5 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the gentamicin level is 6 mg/L. The half-life is 2.5 h, and the drug is eliminated by first-order kinetics. What is the level C 5 h later?

C₀ = 6 mg/Lt½ = 2.5 ht = 5 h
C = mg/L
3.Medium
110t (h)C (mg/L)1 h6 mg/L3 h3.4 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of gentamicin, the level is 6 mg/L at 1 h and 3.4 mg/L at 3 h. Assume first-order elimination. Find the half-life t½.

C1 = 6 mg/L (1 h)C2 = 3.4 mg/L (3 h)
t½ = h
4.Medium
110t (h)C (mg/L)1 h6 mg/L3 h3 mg/L

Practice exercise (made-up values, not clinical guidance). After an IV dose of gentamicin, the level is 6 mg/L at 1 h and 3 mg/L at 3 h. Assume first-order elimination. Find the elimination rate constant k.

C1 = 6 mg/L (1 h)C2 = 3 mg/L (3 h)
k = h⁻¹
5.Hard
Vd = 7 L/kg0.2 → 0.8 mcg/LLD = ? mcg81 kg · S = 1 · F = 0.7

Practice exercise (made-up values, not clinical guidance). An 81 kg patient has a digoxin level of 0.2 mcg/L; the target is 0.8 mcg/L. The volume of distribution is 7 L/kg and the tablets have F = 0.7. What extra loading dose LD raises the level to the target?

81 kgVd = 7 L/kgC = 0.2 → 0.8 mcg/LF = 0.7
LD = mcg
6.Hard
VCss,avg​ = 15 mg/LD = ? mg · q8hCL = 0.03 L/kg/h70 kg · S = 1 · F = 1

Practice exercise (made-up values, not clinical guidance). A 70 kg patient takes oral theophylline (F = 1) every 8 h. The clearance is 0.03 L/kg/h. What dose D in mg gives an average steady-state level of 15 mg/L?

CL = 0.03 L/kg/hτ = 8 hS = 1F = 170 kgCss,avg = 15 mg/L
D = mg

Answer key

  1. 1. t½ = 1.998 h
  2. 2. C = 1.5 mg/L
  3. 3. t½ = 2.441 h
  4. 4. k = 0.3466 h⁻¹
  5. 5. LD = 486 mcg
  6. 6. D = 252 mg

Full step-by-step solutions: practise this topic on examproblems.com.