Clinical pharmacokinetics worksheet with answers

Free printable Clinical pharmacokinetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
110100t (h)C (mg/L)10 mg/L1 hC = ?

Practice exercise (made-up values, not clinical guidance). Just after an IV dose, the tobramycin level is 10 mg/L. The half-life is 2 h, and the drug is eliminated by first-order kinetics. What is the level C 1 h later?

C₀ = 10 mg/Lt½ = 2 ht = 1 h
C = mg/L
2.Easy
110100t (h)CC₀t½ = ?C₀/2

Practice exercise (made-up values, not clinical guidance). The elimination rate constant of digoxin in a patient is 0.0193 h⁻¹. Find the half-life t½.

k = 0.0193 h⁻¹
t½ = h
3.Medium
VCss​ = 15 mg/LR = ? mg/hCL = 0.04 L/kg/h84 kg

Practice exercise (made-up values, not clinical guidance). An 84 kg patient receives a theophylline infusion. The clearance is 0.04 L/kg/h. What infusion rate R in mg/h gives a steady-state level of 15 mg/L?

84 kgCL = 0.04 L/kg/hCss = 15 mg/L
R = mg/h
4.Medium
110100t (h)C (mg/L)C₀ = 12 mg/Lt½ = 2 hC₀/2

Practice exercise (made-up values, not clinical guidance). A patient receives an IV bolus of 270 mg of tobramycin. The level back-extrapolated to time zero is 12 mg/L and the half-life is 2 h. Find the clearance CL in L/h.

D = 270 mgC₀ = 12 mg/Lt½ = 2 h
CL = L/h
5.Hard
56 kg75 · manSCr 1.8 mg/dLCrCl → τ = ? h

Practice exercise (made-up values, not clinical guidance). A 75-year-old man weighs 56 kg and has a serum creatinine of 1.8 mg/dL (159 µmol/L). Estimate the creatinine clearance with Cockcroft–Gault: CrCl (mL/min) = (140 − age) × weight (kg)/(72 × SCr in mg/dL), × 0.85 for women. The usual tobramycin regimen is 120 mg every 8 h for a creatinine clearance of 120 mL/min. Keeping the dose, the interval is lengthened in proportion to the fall in clearance. Find the new dosing interval τ. Round to one decimal place.

75 years56 kgmanSCr = 1.8 mg/dL120 mg q8hCrCl normal 120 mL/min
τ = h
6.Hard
Vd = 0.5 L/kg4.5 → 15 mg/LLD = ? mg91 kg · S = 0.8 · F = 1

Practice exercise (made-up values, not clinical guidance). A 91 kg patient has a theophylline level of 4.5 mg/L; the target is 15 mg/L. The drug is given intravenously as aminophylline (S = 0.8), and the volume of distribution is 0.5 L/kg. What extra loading dose LD raises the level to the target?

91 kgVd = 0.5 L/kgC = 4.5 → 15 mg/LS = 0.8
LD = mg

Answer key

  1. 1. C = 7.071 mg/L
  2. 2. t½ = 35.91 h
  3. 3. R = 50.4 mg/h
  4. 4. CL = 7.798 L/h
  5. 5. τ = 34.2 h
  6. 6. LD = 597.2 mg

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