For z₁ = 8 − j3 and z₂ = 6 − j2, find the modulus of the quotient, |z₁/z₂|.
Complex numbers worksheet with answers
1.Easy
z₁ = 8 − j3z₂ = 6 − j2
|z₁/z₂| =
2.Easy
The Argand diagram shows z₁ = 5 + j2 and z₂ = −1 − j3. Click the point that represents z₁ − z₂.
z₁ = 5 + j2z₂ = −1 − j3
- 1A (6 − j5)
- 2B (−6 − j5)
- 3C (6 + j5)
- 4D (5 + j6)
3.Medium
Write z = −1 + j8 in exponential form r·ejθ. Give θ in radians, between −π and π.
z = −1 + j8
θ = rad
4.Medium
Write z = 3∠160° in rectangular form a + jb and give the real part a.
r = 3θ = 160°
a =
5.Hard
One root of z³ − 9z² + 31z − 39 = 0 is z₁ = 3 + j2. The coefficients are real. Find the real root r.
z₁ = 3 + j2
r =
6.Hard
Solve z² − 2z + 5 = 0. The roots are a ± jb; find the real part a.
p = −2q = 5
a =
Answer key
- 1. |z₁/z₂| = 1.351
- 2. C (6 + j5)
- 3. θ = 1.695 rad
- 4. a = −2.819
- 5. r = 3
- 6. a = 1
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