For z₁ = 7 − j8 and z₂ = 3 + j4, find the imaginary part of the product z₁·z₂.
Complex numbers worksheet with answers
1.Easy
z₁ = 7 − j8z₂ = 3 + j4
Im(z₁z₂) =
2.Easy
For z₁ = −3 + j6 and z₂ = 6 − j4, find the modulus of the product, |z₁z₂|.
z₁ = −3 + j6z₂ = 6 − j4
|z₁z₂| =
3.Medium
Find the argument θ of z = −3 − j8 in degrees, as the principal value between −180° and 180°.
z = −3 − j8
θ = °
4.Medium
Find the argument θ of z = 3 + j6 in degrees, as the principal value between −180° and 180°.
z = 3 + j6
θ = °
5.Hard
One root of z³ + 3z² + 7z + 85 = 0 is z₁ = 1 + j4. The coefficients are real. Find the real root r.
z₁ = 1 + j4
r =
6.Hard
One root of z³ + 3z² − 8z − 30 = 0 is z₁ = −3 + j. The coefficients are real. Find the real root r.
z₁ = −3 + j
r =
Answer key
- 1. Im(z₁z₂) = 4
- 2. |z₁z₂| = 48.37
- 3. θ = −110.6 °
- 4. θ = 63.43 °
- 5. r = −5
- 6. r = 3
Full step-by-step solutions: practise this topic on examproblems.com.