DC motors worksheet with answers

Free printable DC motors worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
+−240 VRa​M+−E = 232 Vn = 3000 rpmT

A DC motor turns at 3000 rpm, and its back-EMF at that speed is 232 V. Find the motor constant k in V·s/rad.

E = 232 Vn = 3000 rpm
k = V·s/rad
2.Easy
+−24 VRa​Ia​ = 4 AM+−EωT = ?

A permanent-magnet DC motor has the torque constant k = 0.5 N·m/A. Find the torque T it develops at an armature current of 4 A.

k = 0.5 N·m/AIa = 4 A
T = N·m
3.Medium
T (N·m)n (rpm)15 N·mn0​n = ?

A DC motor (k = 0.75 N·m/A, Ra = 0.8 Ω) runs from 240 V and drives a load torque of 15 N·m. Find its speed n in rpm.

V = 240 Vk = 0.75 N·m/ARa = 0.8 ΩT = 15 N·m
n = rpm
4.Medium
T (N·m)n (rpm)2 N·mn0​nFL​

A DC motor (k = 0.5 V·s/rad, Ra = 1 Ω) runs from 120 V. At full load it draws 4 A. Neglecting the no-load current, find its speed regulation SR = (n₀ − nFL)/nFL in percent.

V = 120 Vk = 0.5 V·s/radRa = 1 ΩIFL = 4 A
SR = %
5.Hard
+−48 VRa​ = 0.8 ΩIa​: 4 → 8 AM+−En = ?T

A separately excited DC motor on 48 V (Ra = 0.8 Ω) runs at 1800 rpm with an armature current of 4 A. The load changes and the current becomes 8 A, with the field unchanged. Find the new speed n2.

V = 48 VRa = 0.8 Ωn1 = 1800 rpmIa1 = 4 AIa2 = 8 A
n2 = rpm
6.Hard
+−240 VRa​ = 0.25 ΩIa​: 30 → 18 AM+−En = ?T

A separately excited DC motor on 240 V (Ra = 0.25 Ω) runs at 1800 rpm with an armature current of 30 A. The load changes and the current becomes 18 A, with the field unchanged. Find the new speed n2.

V = 240 VRa = 0.25 Ωn1 = 1800 rpmIa1 = 30 AIa2 = 18 A
n2 = rpm

Answer key

  1. 1. k = 0.7385 V·s/rad
  2. 2. T = 2 N·m
  3. 3. n = 2852 rpm
  4. 4. SR = 3.448 %
  5. 5. n2 = 1671 rpm
  6. 6. n2 = 1823 rpm

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