DC motors worksheet with answers

Free printable DC motors worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
+−220 VRa​ = 2 ΩIa​ = ?M+−E = 0n = 0T

A DC motor with an armature resistance of 2 Ω is switched directly onto a 220 V supply. Its normal full-load current is 10 A. Find the armature current Istart at the moment of starting.

V = 220 VRa = 2 Ω
Istart = A
2.Easy
+−24 VRa​Ia​ = 2 AM+−EωT = ?

A permanent-magnet DC motor has the torque constant k = 0.1 N·m/A. Find the torque T it develops at an armature current of 2 A.

k = 0.1 N·m/AIa = 2 A
T = N·m
3.Medium
T (N·m)n (rpm)n0​ = ?

A DC motor with k = 1 V·s/rad runs from 110 V. Neglecting all losses at no load, find its no-load speed n0 in rpm.

V = 110 Vk = 1 V·s/rad
n0 = rpm
4.Medium
+−24 VRa​ = 0.25 ΩIa​ = 6 AM+−EωT

A DC motor draws 6 A from a 24 V supply. Its armature resistance is 0.25 Ω and its rotational (friction, windage and iron) losses are 11 W. Find its efficiency η.

V = 24 VIa = 6 ARa = 0.25 ΩProt = 11 W
η = %
5.Hard
+−110 VRs​ = ?Ra​ = 2 ΩM+−En = 300 rpmT = 3 N·m

A DC motor (k = 1.5 V·s/rad, Ra = 2 Ω) on a fixed 110 V supply drives a load of 3 N·m. Find the series resistance Rs that slows it down to 300 rpm.

V = 110 Vk = 1.5 V·s/radRa = 2 ΩT = 3 N·mn = 300 rpm
Rs = Ω
6.Hard
+−24 VRa​ = 0.25 ΩIa​: 5 → 2 AM+−En = ?T

A separately excited DC motor on 24 V (Ra = 0.25 Ω) runs at 1800 rpm with an armature current of 5 A. The load changes and the current becomes 2 A, with the field unchanged. Find the new speed n2.

V = 24 VRa = 0.25 Ωn1 = 1800 rpmIa1 = 5 AIa2 = 2 A
n2 = rpm

Answer key

  1. 1. Istart = 110 A
  2. 2. T = 0.2 N·m
  3. 3. n0 = 1050 rpm
  4. 4. η = 86.11 %
  5. 5. Rs = 29.44 Ω
  6. 6. n2 = 1859 rpm

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