The propagation delay of every gate is written under it. Find the worst-case propagation delay tpd from the inputs to the output F.
Digital logic: gates, K-maps & flip-flops worksheet with answers
The function F = (A′·B′)·C is 1 for exactly one combination of the inputs. Click that row of the truth table.
- 1ABC = 000
- 2ABC = 001
- 3ABC = 010
- 4ABC = 011
- 5ABC = 100
- 6ABC = 101
- 7ABC = 110
- 8ABC = 111
Use the Karnaugh map to find the minimal product-of-sums (POS) form of F(A, B, C) = Σm(2, 3, 4, 5, 6). How many sum terms (factors) N does it have?
In this Karnaugh map exactly one 1 has no neighbouring 1, so it stays a group of one cell (a full minterm of four literals) in the minimal SOP form. Neighbours across the map edges count. Click that cell.
- 1AB = 00, CD = 00
- 2AB = 00, CD = 01
- 3AB = 00, CD = 11
- 4AB = 00, CD = 10
- 5AB = 01, CD = 00
- 6AB = 01, CD = 01
- 7AB = 01, CD = 11
- 8AB = 01, CD = 10
- 9AB = 11, CD = 00
- 10AB = 11, CD = 01
- 11AB = 11, CD = 11
- 12AB = 11, CD = 10
- 13AB = 10, CD = 00
- 14AB = 10, CD = 01
- 15AB = 10, CD = 11
- 16AB = 10, CD = 10
A 3-bit binary down counter starts at 1 (decimal, Q = 001). Which count Q (in decimal) does it show after 20 clock pulses?
A 4-bit shift register Q₃Q₂Q₁Q₀ holds 0011. At every clock edge the bits shift one place to the right (Q₃ → Q₂ → Q₁ → Q₀, Q₀ is lost) and the serial input enters Q₃. The serial input is 0, 0, 1, 0, 1 at the 5 edges. Give the final state Q = Q₃Q₂Q₁Q₀ as a decimal number.
Answer key
- 1. tpd = 11 ns
- 2. ABC = 001
- 3. N = 2
- 4. AB = 11, CD = 00
- 5. Q = 5
- 6. Q = 10
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