Diodes & transistors worksheet with answers

Free printable Diodes & transistors worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
+−12 VR = ?3.2 V5 mA

A blue LED with a forward voltage of 3.2 V runs from a 12 V supply through a series resistor. Find the resistance R that sets the LED current to 5 mA.

Vs = 12 VVF = 3.2 VI = 5 mA
R = Ω
2.Easy
+−Vs​10 VR1​ = 330 ΩR2​ = 680 ΩID​ = ?

A 10 V DC source is connected through resistor R₁ = 330 Ω to a node X. From node X to the source’s negative terminal there are two parallel paths: resistor R₂ = 680 Ω, and a silicon diode with its anode at X. Use the constant-drop model with 0.7 V. Find the diode current ID in mA.

Vs = 10 VR1 = 330 ΩR2 = 680 ΩVD = 0.7 V
ID = mA
3.Medium
RC​ = 2.2 kΩβ = 80IC​ = ?RE​ = 1 kΩVCC​ = 12 VR1​ = 39 kΩR2​ = 8.2 kΩ

An NPN transistor with β = 80 has voltage-divider bias from VCC = 12 V: R₁ = 39 kΩ from VCC to the base and R₂ = 8.2 kΩ from the base to ground. The collector resistor is RC = 2.2 kΩ and the emitter resistor is RE = 1 kΩ. Take VBE = 0.7 V and use the Thévenin equivalent of the divider (do not neglect the base current). Find the collector current IC in mA.

VCC = 12 VR1 = 39 kΩR2 = 8.2 kΩRC = 2.2 kΩRE = 1 kΩβ = 80
IC = mA
4.Medium
RC​ = 470 Ωβ = 120VCC​ = 9 VRB​ = 270 kΩ

An NPN transistor with β = 120 is biased by a base resistor RB = 270 kΩ from the supply VCC = 9 V. The collector resistor is RC = 470 Ω and the emitter is grounded. Take VBE = 0.7 V and assume the transistor is in the active region. Find the collector–emitter voltage VCE.

VCC = 9 VRB = 270 kΩRC = 470 Ωβ = 120VBE = 0.7 V
VCE = V
5.Hard
V (V)I (mA)0.65640Q = ?

A diode is modelled as 0.65 V in series with 5 Ω (it conducts above 0.65 V). It is in series with a 150 Ω resistor across a 6 V supply. Find the operating current ID where the diode line meets the load line.

Vs = 6 VR = 150 ΩV0 = 0.65 Vrd = 5 Ω
ID = mA
6.Hard
RC​ = 330 Ωβ = 150VCC​ = 12 V5 VRB​ = ?

An NPN transistor with β = 150 switches a 330 Ω load resistor connected between VCC = 12 V and its collector. The emitter is grounded. The base is driven from a 5 V logic output through a base resistor RB. Take VBE = 0.7 V and VCE(sat) = 0.2 V. Find the largest base resistor RB, in kΩ, that still drives the transistor just into saturation.

VCC = 12 VRC = 330 Ωβ = 150Vin = 5 VVBE = 0.7 VVCE(sat) = 0.2 V
RB = kΩ

Answer key

  1. 1. R = 1760 Ω
  2. 2. ID = 27.15 mA
  3. 3. IC = 1.262 mA
  4. 4. VCE = 7.266 V
  5. 5. ID = 34.52 mA
  6. 6. RB = 18.04 kΩ

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