Diodes & transistors worksheet with answers

Free printable Diodes & transistors worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
+−Vs​5 VR1​ = 1 kΩR2​ = 3.3 kΩID​ = ?

A 5 V DC source is connected through resistor R₁ = 1 kΩ to a node X. From node X to the source’s negative terminal there are two parallel paths: resistor R₂ = 3.3 kΩ, and a silicon diode with its anode at X. Use the constant-drop model with 0.7 V. Find the diode current ID in mA.

Vs = 5 VR1 = 1 kΩR2 = 3.3 kΩVD = 0.7 V
ID = mA
2.Easy
+−20 V220 Ω9.1 VIR​ = ?

A 9.1 V Zener diode is fed from 20 V through a 220 Ω resistor, with no load connected. Find the current IR in the resistor.

Vin = 20 VVZ = 9.1 VR = 220 Ω
IR = mA
3.Medium
RC​ = 1.5 kΩβ = 200VCC​ = 9 VRB​ = 820 kΩ

An NPN transistor with β = 200 is biased by a base resistor RB = 820 kΩ from the supply VCC = 9 V. The collector resistor is RC = 1.5 kΩ and the emitter is grounded. Take VBE = 0.7 V and assume the transistor is in the active region. Find the collector–emitter voltage VCE.

VCC = 9 VRB = 820 kΩRC = 1.5 kΩβ = 200VBE = 0.7 V
VCE = V
4.Medium
RC​ = 470 Ωβ = 120IC​ = ?VCC​ = 15 VRB​ = 560 kΩ

An NPN transistor with β = 120 is biased by a base resistor RB = 560 kΩ from the supply VCC = 15 V. The collector resistor is RC = 470 Ω and the emitter is grounded. Take VBE = 0.7 V and assume the transistor is in the active region. Find the collector current IC in mA.

VCC = 15 VRB = 560 kΩRC = 470 Ωβ = 120VBE = 0.7 V
IC = mA
5.Hard
V (V)I (mA)0.651254.55Q = ?

A diode is modelled as 0.65 V in series with 25 Ω (it conducts above 0.65 V). It is in series with a 220 Ω resistor across a 12 V supply. Find the operating current ID where the diode line meets the load line.

Vs = 12 VR = 220 ΩV0 = 0.65 Vrd = 25 Ω
ID = mA
6.Hard
+−≥ 18 VR = ?5.1 V≤ 25 mA

A 5.1 V Zener regulator must supply up to 25 mA to a load. The input can drop to 18 V, and the Zener needs at least 2 mA to regulate. Find the largest series resistance Rmax that keeps it regulating.

Vin,min = 18 VVZ = 5.1 VIL,max = 25 mAIZ,min = 2 mA
Rmax = Ω

Answer key

  1. 1. ID = 4.088 mA
  2. 2. IR = 49.55 mA
  3. 3. VCE = 5.963 V
  4. 4. IC = 3.064 mA
  5. 5. ID = 46.33 mA
  6. 6. Rmax = 477.8 Ω

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