Diodes & transistors worksheet with answers

Free printable Diodes & transistors worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
+−Vs​5 VR1​ = 1.5 kΩR2​ = 10 kΩID​ = ?

A 5 V DC source is connected through resistor R₁ = 1.5 kΩ to a node X. From node X to the source’s negative terminal there are two parallel paths: resistor R₂ = 10 kΩ, and a silicon diode with its anode at X. Use the constant-drop model with 0.7 V. Find the diode current ID in mA.

Vs = 5 VR1 = 1.5 kΩR2 = 10 kΩVD = 0.7 V
ID = mA
2.Easy
+−15 V330 Ω12 VIR​ = ?

A 12 V Zener diode is fed from 15 V through a 330 Ω resistor, with no load connected. Find the current IR in the resistor.

Vin = 15 VVZ = 12 VR = 330 Ω
IR = mA
3.Medium
RC​ = 5.6 kΩβ = 200IC​ = ?RE​ = 1.5 kΩVCC​ = 20 VR1​ = 47 kΩR2​ = 10 kΩ

An NPN transistor with β = 200 has voltage-divider bias from VCC = 20 V: R₁ = 47 kΩ from VCC to the base and R₂ = 10 kΩ from the base to ground. The collector resistor is RC = 5.6 kΩ and the emitter resistor is RE = 1.5 kΩ. Take VBE = 0.7 V and use the Thévenin equivalent of the divider (do not neglect the base current). Find the collector current IC in mA.

VCC = 20 VR1 = 47 kΩR2 = 10 kΩRC = 5.6 kΩRE = 1.5 kΩβ = 200
IC = mA
4.Medium
+−20 V330 Ω5.1 V1000 ΩIZ​ = ?

A 5.1 V Zener regulator is fed from 20 V through 330 Ω and supplies a 1000 Ω load. Find the Zener current IZ.

Vin = 20 VVZ = 5.1 VR = 330 ΩRL = 1000 Ω
IZ = mA
5.Hard
+−≤ 13 V680 Ω3.3 V

A 3.3 V Zener regulator has a 680 Ω series resistor. The input can rise to 13 V, and the load may be disconnected. Find the largest power PZ,max the Zener must dissipate.

Vin,max = 13 VVZ = 3.3 VR = 680 Ω
PZ,max = mW
6.Hard
RC​ = 100 Ωβ = 200VCC​ = 9 V3.3 VRB​ = ?

An NPN transistor with β = 200 switches a 100 Ω load resistor connected between VCC = 9 V and its collector. The emitter is grounded. The base is driven from a 3.3 V logic output through a base resistor RB. Take VBE = 0.7 V and VCE(sat) = 0.2 V. For reliable switching, design for a base current 4 times the minimum needed for saturation. Find RB in kΩ.

VCC = 9 VRC = 100 Ωβ = 200Vin = 3.3 VVBE = 0.7 VVCE(sat) = 0.2 Voverdrive = 4
RB = kΩ

Answer key

  1. 1. ID = 2.797 mA
  2. 2. IR = 9.091 mA
  3. 3. IC = 1.814 mA
  4. 4. IZ = 40.05 mA
  5. 5. PZ,max = 47.07 mW
  6. 6. RB = 1.477 kΩ

Full step-by-step solutions: practise this topic on examproblems.com.