How many usable host addresses H are there in an IPv4 subnet with prefix /24?
IPv4 subnetting worksheet with answers
1.Easy
/24
H =
2.Easy
An access list must match the network 172.16.0.0/23. Access lists use a wildcard mask, the inverse of the subnet mask. What is the third octet x of the wildcard mask?
/23
x =
3.Medium
The network 10.89.100.0/22 is divided into equal subnets with prefix /27. How many subnets N are there?
10.89.100.0/22/27
N =
4.Medium
The network 192.168.10.0/24 must be divided into at least 12 equal subnets. If you borrow as few bits as possible, how many usable hosts H does each subnet have?
192.168.10.0/2412 subnets
H =
5.Hard
A host has the address 10.20.103.234/30. What is the fourth octet x of the last usable host address in its subnet?
10.20.103.234/30
x =
6.Hard
A host has the address 10.20.34.114/27. What is the fourth octet x of the last usable host address in its subnet?
10.20.34.114/27
x =
Answer key
- 1. H = 254
- 2. x = 1
- 3. N = 32
- 4. H = 14
- 5. x = 234
- 6. x = 126
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