How many usable host addresses H are there in an IPv4 subnet with prefix /27?
IPv4 subnetting worksheet with answers
1.Easy
/27
H =
2.Easy
How many usable host addresses H are there in an IPv4 subnet with prefix /25?
/25
H =
3.Medium
The network 192.168.10.0/24 must be divided into at least 6 equal subnets. If you borrow as few bits as possible, how many usable hosts H does each subnet have?
192.168.10.0/246 subnets
H =
4.Medium
The network 192.168.209.0/24 is divided into /29 subnets, numbered 1, 2, 3, … from the lowest address (subnet 1 starts at .0). What is the fourth octet x of the network address of subnet 5?
192.168.209.0/24/29subnet 5 (subnet 1 starts at .0)
x =
5.Hard
A host has the address 10.20.45.25/28. What is the fourth octet x of its network address?
10.20.45.25/28
x =
6.Hard
A router has routes to these networks: 10.200.105.0/24, 10.200.106.0/24. What is the longest prefix length p of a single summary route that covers all of them?
10.200.105.0/24 … 10.200.106.0/24
p =
Answer key
- 1. H = 30
- 2. H = 126
- 3. H = 30
- 4. x = 32
- 5. x = 16
- 6. p = 22
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