A resonance curve peaks at 1.6 MHz, and its half-power points are 80 kHz apart. Find the quality factor Q.
LC resonance, Q factor & bandwidth worksheet with answers
1.Easy
f0 = 1.6 MHzBW = 80 kHz
Q =
2.Easy
An LC circuit with L = 2.2 mH must resonate at 50 kHz. Find the capacitance C in nF.
L = 2.2 mHf0 = 50 kHz
C = nF
3.Medium
A series RLC circuit has R = 5 Ω, L = 10 mH and C = 10 nF. Find its bandwidth BW in Hz.
R = 5 ΩL = 10 mHC = 10 nF
BW = Hz
4.Medium
A series RLC circuit resonates at 100 kHz with Q = 3. Find the lower half-power frequency f1 exactly, in kHz.
f0 = 100 kHzQ = 3
f1 = kHz
5.Hard
A series resonant circuit uses a 22 µH inductor. Which total series resistance R gives a bandwidth of 50 kHz?
L = 22 µHBW = 50 kHz
R = Ω
6.Hard
A parallel tank circuit is made of a 10 nF capacitor and a 10 mH coil with a winding resistance of 2 Ω. At resonance it behaves like a resistor, its dynamic resistance RD = L/(C·r). Find RD in kΩ.
L = 10 mHC = 10 nFr = 2 Ω
RD = kΩ
Answer key
- 1. Q = 20
- 2. C = 4.606 nF
- 3. BW = 79.58 Hz
- 4. f1 = 84.71 kHz
- 5. R = 6.912 Ω
- 6. RD = 500 kΩ
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