Mechanical vibrations worksheet with answers

Free printable Mechanical vibrations worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
k = 40 kN/mm = 40 kgx

A 40 kg mass hangs from a spring with a stiffness of 40 kN/m. Ignore damping. Find the natural frequency fn in Hz.

m = 40 kgk = 40 kN/m
fn = Hz
2.Easy
k = 150 kN/mm = 40 kgx

A 40 kg mass hangs from a spring with a stiffness of 150 kN/m. Ignore damping. Find the natural circular frequency ωn in rad/s.

m = 40 kgk = 150 kN/m
ωn = rad/s
3.Medium
tx40 mm2 cycles18.8 mm

In a free-vibration test of a damped mass–spring system, a displacement peak of 40 mm is followed 2 cycles later by a peak of 18.8 mm. Find the damping ratio ζ.

x0 = 40 mmx2 = 18.8 mmn = 2
ζ =
4.Medium
k = 25 kN/mc = 190 N·s/mm = 150 kg

A 150 kg mass is supported by a spring with a stiffness of 25 kN/m and a viscous damper with a damping coefficient of 190 N·s/m. Find the damping ratio ζ.

m = 150 kgk = 25 kN/mc = 190 N·s/m
ζ =
5.Hard
k1​ = 15k2​ = 5k3​ = 50m = 50 kg

A 50 kg mass hangs from spring k₃ = 50 kN/m. The top of k₃ is attached to a rigid bar that hangs from two springs side by side, k₁ = 15 kN/m and k₂ = 5 kN/m; the bar stays level. Ignore damping and the masses of the springs and bar. Find the natural frequency fn of vertical vibration in Hz.

m = 50 kgk1 = 15 kN/mk2 = 5 kN/mk3 = 50 kN/m
fn = Hz
6.Hard
k1​ = 40k2​ = 25m = 20 kg

A 20 kg mass hangs from two springs side by side (in parallel), with stiffnesses k₁ = 40 kN/m and k₂ = 25 kN/m. The mass stays level. Find the equivalent stiffness keq of the spring system in kN/m.

m = 20 kgk1 = 40 kN/mk2 = 25 kN/m
keq = kN/m

Answer key

  1. 1. fn = 5.033 Hz
  2. 2. ωn = 61.24 rad/s
  3. 3. ζ = 0.05997
  4. 4. ζ = 0.04906
  5. 5. fn = 2.69 Hz
  6. 6. keq = 65 kN/m

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