Mechanical vibrations worksheet with answers

Free printable Mechanical vibrations worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
kmδst​ = 2 mmunloaded

A machine rests on spring mounts, which compress by 2 mm under its weight. Treat it as an undamped single-degree-of-freedom system and use g = 9.81 m/s². Find the natural frequency fn of vertical vibration in Hz.

δst = 2 mmg = 9.81 m/s²
fn = Hz
2.Easy
k = 80 kN/mm = 12 kgx

A 12 kg mass hangs from a spring with a stiffness of 80 kN/m. Ignore damping. Find the natural circular frequency ωn in rad/s.

m = 12 kgk = 80 kN/m
ωn = rad/s
3.Medium
k = 200 kN/mζ = 0.6m = 500 kg

A 500 kg mass on a spring with a stiffness of 200 kN/m has a viscous damper giving a damping ratio of 0.6. Find the damped natural frequency fd of its free vibration in Hz.

m = 500 kgk = 200 kN/mζ = 0.6
fd = Hz
4.Medium
k = 20 kN/mζ = 0.6m = 2 kg

A 2 kg mass on a spring with a stiffness of 20 kN/m has a viscous damper giving a damping ratio of 0.6. Find the damped natural frequency fd of its free vibration in Hz.

m = 2 kgk = 20 kN/mζ = 0.6
fd = Hz
5.Hard
k1​ = 15k2​ = 5m = 50 kg

A 50 kg mass hangs from two springs connected end to end (in series): the upper spring has k₁ = 15 kN/m and the lower one k₂ = 5 kN/m. Ignore damping and the masses of the springs. Find the natural frequency fn of vertical vibration in Hz.

m = 50 kgk1 = 15 kN/mk2 = 5 kN/m
fn = Hz
6.Hard
k1​ = 10k2​ = 50m = 25 kg

A 25 kg mass hangs from two springs connected end to end (in series): the upper spring has k₁ = 10 kN/m and the lower one k₂ = 50 kN/m. Find the equivalent stiffness keq of the spring system in kN/m.

m = 25 kgk1 = 10 kN/mk2 = 50 kN/m
keq = kN/m

Answer key

  1. 1. fn = 11.15 Hz
  2. 2. ωn = 81.65 rad/s
  3. 3. fd = 2.546 Hz
  4. 4. fd = 12.73 Hz
  5. 5. fn = 1.378 Hz
  6. 6. keq = 8.333 kN/m

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