A point in a loaded part has σₓ = 160 MPa, σᵧ = −80 MPa and τₓᵧ = 10 MPa (tension positive). Find the smallest principal stress σ2.
Mohr’s circle & stress transformation worksheet with answers
At a point in a loaded part the in-plane principal stresses are σ₁ = 60 MPa and σ₂ = −80 MPa (tension positive). Find the normal stress σavg that acts on the planes of maximum in-plane shear stress.
A point in a loaded part has σₓ = −10 MPa, σᵧ = 100 MPa and τₓᵧ = −60 MPa (tension positive). Find the angle θp from the x-axis to the direction of the largest principal stress, between −90° and 90°.
A point has σₓ = −40 MPa, σᵧ = 0 MPa and τₓᵧ = 30 MPa (tension positive). Find the angle θs, between −90° and 90°, from the x-axis to the normal of the plane on which the shear stress has its maximum positive value +R (shear positive in the same sense as τₓᵧ).
A point in a loaded part has σₓ = 20 MPa, σᵧ = 120 MPa and τₓᵧ = −60 MPa (tension positive). Find the normal stress σθ on a plane whose normal is rotated 60° counter-clockwise from the x-axis.
A point in a loaded part has σₓ = 160 MPa, σᵧ = 0 MPa and τₓᵧ = 60 MPa (tension positive). Find the normal stress σθ on a plane whose normal is rotated 35° counter-clockwise from the x-axis.
Answer key
- 1. σ2 = −80.42 MPa
- 2. σavg = −10 MPa
- 3. θp = −66.26 °
- 4. θs = 16.85 °
- 5. σθ = 43.04 MPa
- 6. σθ = 163.7 MPa
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