32 g of Na2CO3 (M = 105.99 g/mol) is dissolved in water to make 500 mL of solution. Find the molarity c.
Molarity & dilution worksheet with answers
1.Easy
m = 32 gM = 105.99 g/molV = 500 mL
c = mol/L
2.Easy
What mass m of KMnO4 (M = 158.03 g/mol) do you need to make 1000 mL of a 0.2 mol/L solution?
V = 1000 mLc = 0.2 mol/LM = 158.03 g/mol
m = g
3.Medium
You need 1000 mL of 0.05 mol/L solution and have a 5 mol/L stock solution. How much water Vwater do you add to the stock solution?
c1 = 5 mol/Lc2 = 0.05 mol/LV2 = 1000 mL
Vwater = mL
4.Medium
You need 250 mL of 0.3 mol/L solution and have a 2.5 mol/L stock solution. What volume V1 of stock solution do you need?
c1 = 2.5 mol/Lc2 = 0.3 mol/LV2 = 250 mL
V1 = mL
5.Hard
50 mL of a 0.2 mol/L solution is mixed with 500 mL of a 0.1 mol/L solution of the same substance. Find the concentration c of the mixture (volumes are additive).
c1 = 0.2 mol/LV1 = 50 mLc2 = 0.1 mol/LV2 = 500 mL
c = mol/L
6.Hard
150 mL of a 2 mol/L solution is mixed with 400 mL of a 0.6 mol/L solution of the same substance. Find the concentration c of the mixture (volumes are additive).
c1 = 2 mol/LV1 = 150 mLc2 = 0.6 mol/LV2 = 400 mL
c = mol/L
Answer key
- 1. c = 0.6038 mol/L
- 2. m = 31.61 g
- 3. Vwater = 990 mL
- 4. V1 = 30 mL
- 5. c = 0.1091 mol/L
- 6. c = 0.9818 mol/L
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